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3 years ago

530 divided by 16 give the quotient and remainder

Mathematics

1 answer:

damaskus [11]3 years ago

6 0

33
_____
16 | 530
48
-------
50
48
----------
2

quotient = 33
remainder = 2

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If f(x)=3x+2and g(x)=x^2-9 find (f-g)(x)

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Step-by-step explanation:

If f(x)=3x+2and g(x)=x^2-9

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f(x)- g(x) = [3x + 2] - [x^2 - 9]

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A right prism has height 7½ and triangular bases with sides of length 5, 12, and 13 What is the: Total Surface Area of the Prism

sdas [7]

Given:

A right prism has height 7½ and triangular bases with sides of length 5, 12, and 13.

To find:

The total surface area of the prism.

Solution:

We have,

Height of prism = 7½ = 7.5

Sides of triangular base are 5, 12, 13. These sides of Pythagorean triplets because

$5^2+12^2=13^2$

$25+144=169$

$169=169$

So, the base of the prism is a right triangle.

Area of a triangle is

$Area=\dfrac{1}{2}\times base \times height$

$A_1=\dfrac{1}{2}\times 5\times 12$

$A_1=30$

The area of the base is equal to the area of the top, i.e., $A_2=30$ sq units.

Perimeter of the base is

$P=5+12+13$

$P=30$

The curved surface area of the prism is

$CSA=\text{Perimeter of the base}\times \text{Height of the prism}$

$CSA=30\times 7.5$

$CSA=225$

Now, the total area of the prism is

$A=A_1+A_2+CSA$

$A=30+30+225$

$A=285$

Therefore, the total surface area of the triangular prism is 285 square units.

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3 years ago

F(x)=9x^2 <br><br> g(x)= sqrt 12-x/3<br><br> (f o g)(-4)

Slav-nsk [51]

$f(x)=9x^2 \\ g(x)=\frac{\sqrt{12-x}}{3} \\$ So,first step is to write $(fog)(-4)) =f[g(-4)] \\$

Now we start from inner paranthesis ,we need to first find value of $g(-4) =\frac{\sqrt{12-(-4)}}{3}\\ =\frac{\sqrt{12+4}}{3}\\
=\frac{\sqrt{16}}{3}\\
=\frac{4}{3}\\
(fog)(-4)) =f[g(-4)] =f(\frac{4}{3}) =9(4/3)^{2} =9*(16/9) =144/9 =16$

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3 years ago

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crimeas [40]

It would be 75 units in length and 18 units in width.

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3 years ago