Answer:
the answer is the 3rd one
Here is a screen shot of what I found...hope this helps =)
Answer:
f ( x ) does not satisfy the mean value theorem
Step-by-step explanation:
The given data :-
- f(x) = 3x - 4 cos ( 2x + 1 )
- f'(x) = 3 +8 sin ( 2x + 1 )
- The interval [ -1 , 2 ]
Solution :-
i) f(x) is continuous on [ -1 , 2 ]
ii) f(x) is derivable on ( -1 , 2 )
f ( -1 ) = 3 * (-1 ) - 4 cos [ 2 * ( -1 ) + 1 ] = - 3 + cos (-1 ) = - 3 - 4 * 0.9998 = - 6.992
f ( 2 ) = 3 * 2 - 4 cos ( 4 * 2 + 1 ) = 6 + 4 cos 9 = 6 - 3.9507 = - 3.04924
iii) f ( -1 ) ≠ f ( 2 )
f ( x ) is not real valued function so it does not satisfy the mean value theorem
Answer:
B
Step-by-step explanation:
Getting info from multiple places is better
Solve for n.
0.2(n - 6) = 2.8
Distribute
0.2*n - 0.2*6 = 2.8
0.2n - 1.2 = 2.8
Now inverse operation should be applied
0.2n - 1.2 = 2.8
+ 1.2 +1.2
2.8 + 1.2 = 4
0.2n = 4
0.2n/0.2 = 4/0.2
n = 20
Answer: 20
