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creativ13 [48]
4 years ago
11

Just answer what it asks in the picture PLEASE

Mathematics
1 answer:
Molodets [167]4 years ago
7 0

m∠1 = 30° (by Vertical angle theorem)

m∠A = 80° (by Triangle sum theorem)

m∠D = 80° (by Triangle sum theorem)

The value of x is 7.5 and y is 9.

Solution:

∠ACB and ∠DCE are vertically opposite angles.

Vertical angle theorem:

<em>If two lines are intersecting, then vertically opposite angles are congruent.</em>

⇒ m∠DCE = m∠ACB

⇒ m∠1 = 30° (by Vertical angle theorem)

In triangle ACD,

Triangle sum property:

<em>Sum of the interior angles of the triangle = 180°</em>

⇒ m∠A + m∠C + m∠B = 180°

⇒ m∠A + 30° + 70° = 180°

⇒ m∠A + 100° = 180°

⇒ m∠A = 100° – 180°

⇒ m∠A = 80° (by Triangle sum theorem)

Similarly, m∠D = 80° (by Triangle sum theorem)

In ΔACD and ΔDCE,

All the angles are congruent, so ΔACD and ΔDCE are similar triangles.

<em>In similar triangle corresponding sides are in the same ratio.</em>

$\frac{9}{12}=\frac{x}{10}

Do cross multiplication.

90 = 12x

7.5 = x

Now, to find y:

$\frac{9}{12}=\frac{6}{y}

Do cross multiplication.

9y = 72

Divide by 9, we get

y = 8

Hence the value of x is 7.5 and y is 9.

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Vsevolod [243]

5.\\12\dfrac{3}{10}-7\dfrac{7}{10}=11\dfrac{10+3}{10}-7\dfrac{7}{10}=11\dfrac{13}{10}-7\dfrac{7}{10}=4\dfrac{6}{10}=4\dfrac{6:2}{10:2}=\boxed{5\dfrac{3}{5}}\\\\11-7=4\\\\\dfrac{13}{10}-\dfrac{7}{10}=\dfrac{13-7}{10}=\dfrac{6}{10}\\\\6.\\8\dfrac{1}{6}-3\dfrac{5}{6}=7\dfrac{6+1}{6}-3\dfrac{5}{6}=7\dfrac{7}{6}-3\dfrac{5}{6}=(7-3)+\dfrac{7-5}{6}=4\dfrac{2}{6}=4\dfrac{2:2}{6:2}=\boxed{4\dfrac{1}{3}}

9.\\7\dfrac{1}{6}-2\dfrac{5}{6}=6\dfrac{6+1}{6}-2\dfrac{5}{6}=6\dfrac{7}{6}-2\dfrac{5}{6}=(6-2)+\dfrac{7-5}{6}=4\dfrac{2}{6}=\boxed{4\dfrac{1}{3}}\\\\10.\\9\dfrac{3}{12}-4\dfrac{7}{12}=8\dfrac{12+3}{12}-4\dfrac{7}{12}=8\dfrac{15}{12}-4\dfrac{7}{12}=(8-4)+\dfrac{15-7}{12}=4\dfrac{8}{12}\\\\=4\dfrac{8:4}{12:4}=\boxed{4\dfrac{2}{3}}

5 0
3 years ago
In the past year and a half, Gnarly the dog lost an average of 29pound each month. Today, Gnarly weighs 14 pounds. How much did
tatyana61 [14]

Answer:

449pounds

Step-by-step explanation:

29x15months=435

435+15=449 pounds

P.S. That was one BIG dog.

7 0
3 years ago
The angle 0 lies in Quadrant II . <br>Cos 0 = <br><img src="https://tex.z-dn.net/?f=%20-%20%20%5Cfrac%7B2%7D%7B3%7D%20" id="TexF
mel-nik [20]

Answer:

\tan(\theta)=\frac{-\sqrt{5}}{2}

Step-by-step explanation:

Since we are in quadrant 2, sine is positive.  Since sine is positive and cosine is negative, then tangent is negative.

Now I'm going to find the sine value of this angle given using one of the Pythagorean Identities, namely \sin^2(\theta)+\cos^2(\theta)=1.

If given \cos(\theta)=\frac{-2}{3}, then we have \sin^2(\theta)+(\frac{-2}{3})^2=1 by substitution of \cos(\theta)=\frac{-2}{3}.

Let's solve:

\sin^2(\theta)+(\frac{-2}{3})^2=1 for \sin(\theta).

\sin^2(\theta)+\frac{4}{9}=1

Subtract 4/9 on both sides:

\sin^2(\theta)=1-\frac{4}{9}

Simplify:

\sin^2(\theta)=\frac{5}{9}

Square root both sides:

\sin(\theta)=\sqrt{\frac{5}{9}}

\sin(\theta)=\frac{\sqrt{5}}{\sqrt{9}}

\sin(\theta)=\frac{\sqrt{5}}{3}

===========

\tan(\theta)=\frac{\sin(\theta)}{\cos(\theta)}=\frac{\frac{\sqrt{5}}{3}}{\frac{-2}{3}}

Multiplying top and bottom by 3 gives:

\tan(\theta)=\frac{\sqrt{5}}{-2}

I'm going to move the factor of -1 to the top:

\tan(\theta)=\frac{-\sqrt{5}}{2}

7 0
3 years ago
I'm begging you please help me!!! Thank you ♡
AnnyKZ [126]
With what? there’s no problem.
7 0
3 years ago
On Saturday, a local hamburger shop sold a combined total of 464 hamburgers and cheeseburgers. The number of cheeseburgers sold
Dennis_Churaev [7]
Cheeseburgers= x
Hamburgers= x*3

3x+x=464
4x=464
x=116

Substitute- Cheeseburgers= 116
                   Hamburgers= 3*116=348
Check- 116
           +348
           ____
               464

There are 348 hamburgers.

Hope this helps!
4 0
4 years ago
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