3 years ago

Please help me and I’ll give you brainiest!!!!!!!!! Thank you:)!!!!!

Mathematics

1 answer:

sattari [20]3 years ago

4 0

What you have written down is correct, x=-3

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I need these from least to greatest A.11^4/11^11 B.1/11^-4 C.(11^-3)^-3 D.11^5•11^2

Sliva [168]

Answer:

$\frac{ {11}^{4} }{ {11}^{11} } < \frac{1}{ {11}^{ - 4} } < {11}^{5} . {11}^{2} < ( {11}^{ - 3} )^{ - 3}$

Step-by-step explanation:

$A) \frac{ {11}^{4} }{ {11}^{11} } = {11}^{4 - 11} = {11}^{ - 7} \\ \\ B)\frac{1}{ {11}^{ - 4} } = {11}^{4} \\ \\C) ( {11}^{ - 3} )^{ - 3} = {11}^{ - 3( - 3)} = {11}^{9} \\ \\ D){11}^{5} . {11}^{2} = {11}^{5 + 2} = {11}^{7} \\ \\ \because \: {11}^{ - 7} < {11}^{4} < {11}^{7} < {11}^{9} \\ \\ \therefore \: \frac{ {11}^{4} }{ {11}^{11} } < \frac{1}{ {11}^{ - 4} } < {11}^{5} . {11}^{2} < ( {11}^{ - 3} )^{ - 3}$