Answer:
9.
h(x)=-x-1
let y =-x-1
interchanging role of x & y
x=-y-1
y=-x-1
h-¹(x)=-x-1
again
f(x)=(2-3x)/2
let
y=(2-3x)/2
interchanging role of x & y
x=(2-3y)/2
2x-2=-3y
y=(2-2x)/3
f-¹(x)=(2-2x)/3
<u>G</u><u>i</u><u>v</u><u>e</u><u>n</u><u> </u><u>f</u><u>u</u><u>n</u><u>c</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>a</u><u>r</u><u>e</u><u> </u><u>n</u><u>o</u><u>t</u><u> </u><u>i</u><u>n</u><u>v</u><u>e</u><u>r</u><u>s</u><u>e</u><u> </u><u>o</u><u>f</u><u> </u><u>e</u><u>a</u><u>c</u><u>h</u><u> </u><u>o</u><u>t</u><u>h</u><u>e</u><u>r</u><u>.</u>
10.
f(x)=-x+3
let y=-x+3
interchanging role of x & y
x=-y+3
y=3-x
f-¹(x)=-x+3
equal to g(x)=-x+3
<u>Given function are</u><u> inverse of each other.</u>
Answer:
-0.075
Step-by-step explanation:
[Player R, Player C] cases & outcomes :-
- (Vowel, Vowel) = (0,0)
- (Consonant, Consonant) = (0,0)
- (Vowel, Consonant) = (6,-6)
- (Consonant, Vowel) = (-5,5)
- Prob (R chooses consonant) = 75% = 0.75
- Prob (R chooses vowel) = 1 - 0.75 = 0.25
- Prob (C chooses vowel) = 30% = 0.30
- Prob (C chooses consonant) = 1 - 0.30 = 0.70
Average Loss of R = Expected value of : he choses consonant & C choses vowel; he chooses vowel & C choses consonant
= (0.75)(0.30)(-5) + (0.25)(0.70)(6)
-1.125 + 1.05
= -0.075
Answer:
(8) and
(9) and
(10) and
Step-by-step explanation:
Given [Missing from the question]
Required
Write a system of linear equations
The solutions to this question is open and have different solutions
Solving (8) (-6,-2)
Let the equations be: x + y and 2x - y
--- (1)
-- (2)
So, the equations are:
and
Solving (9) (-12, 18)
Let the equations be: 3x - y and 4x + y
So, the equations are:
and
Solving (9): (2,0)
Let the equations be: x + y and x - y
So, the equations are:
and
-2/3 is a rational number
0.1111.... =1/9 - rational number
-2/3*1/5= -2/15 rational
1/9*1/5=1/45 rational
correct answer A and D
π and √11 are irrational numbers, and when they are multiplied by rational number, they will give irrational number.