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3 years ago

Can you please find the range of these numbers? 18, 16, 19, 15, 17. I will give 16 points

Mathematics

1 answer:

gavmur [86]3 years ago

3 0

Answer: Hi the Range is 4

Step-by-step explanation: The range of a data set in statistics is the difference between the largest and the smallest values. While range does have different meanings within different areas of statistics and mathematics, this is its most basic definition, and is what is used by the provided calculator. Using the same example:

18, 16, 19, 15, 17

19,18,17,16,15

19-15= 4

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A storage trunk is shaped like a rectangular prism. The trunk's volume is 18 cubic feet. The length of the trunk is 6 feet, and

Yuki888 [10]

Answer:

1.5

Step-by-step explanation:

The height is 1.5 because to find the volume of a rectangular prism, you do length x width x height. Without height, you multiply length x width (6x2) and divide that by the volume (18 divided by 12 = 1.5)

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3 years ago

Explain how you can use multiplication to find the volume of the figure. Then find the volume.

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The base of a triangle measures 21 in. What is the measure of the corresponding mid segment of the triangle ?

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3 years ago

A magician’s stage has a rectangle trapdoor which is (x+ 1/2) by 2x ft. The outside rectangle length is (x+ 16) ft.

Katen [24]

Answer:

Part A:- $x +11 ft$ Part B:- $(4x+54)ft$ part C:- $x= 2ft$

Part D:- Yes it satisfy his requirement

Step-by-step explanation:

Given that,

length and breadth of Trapdoor are $(x+ \frac{1}{2} ) by 2x$ ft.

The Outside length of Rectangle is $(x+16 )$ ft.

Part A:- Total area (in square feet) of the stage can be represented by

$x^{2} + 27x+ 176$ . Write an expression for the width of stage.

So, Area of rectangle = $length \times breadth$

$x^{2} + 27x+ 176 = (x+16) \times breadth$

$Breadth = \frac{x^{2} + 27x+ 176}{x+16}$

$Breadth = x+11$ ft. ................(1)

Part B:- Write an expression for the Perimeter of the stage.

Here, Perimeter of Rectangle = $2(L+B)$

= $2(x+16 + x +11)$

= $(4x + 54) ft$

Part C:- The area of trapdoor is $10 ft^{2}$ . Find the value of x.

So, Area of trapdoor = $10 ft^{2}$

$(x +\frac{1}{2}) \times 2x =10 ft^{2}$

$2x^{2} +x - 10 = 0$

$x = \frac{-1-9}{4}$ , $\frac{-1+9}{4}$

$x = \frac{-5}{2}$ , $2$

Hence value of x is $2 ft$ (Neglecting the negative value because

length cannot be negative).

Part D:- The magician wishes to have the area of the stage be at least 20 times the area of the trapdoor. Does this stage satisfy his requirement? Explain.

So, Length of trapdoor is $(2+\frac{1}{2} ) = \frac{5}{2} ft$