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blondinia [14]
3 years ago
10

17.16 is 62.4% of what

Mathematics
2 answers:
slamgirl [31]3 years ago
7 0
Use is over of equals percent over 100. 17.6 would go where is is, and the percent would go in the place of the percent. Crossmultiply and you should get an answer. If you need me to check message me
Zinaida [17]3 years ago
3 0
17.16 is 62.4% of 27.5

Change the percentage (62.4) into a decimal by dividing the percentage by 100:
\frac{62.4}{100} = 0.624

Divide 17.16 by 0.624:
\frac{17.16}{0.624} = 27.5
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6x2 + 150 = 0<br> Can u solve plz I’m in a hurt
Mashutka [201]

Answer:

6x2 + 150 = 0

12x + 150 = 0

12x + 150 = 0

-150         -150

 12x  =   -150

12x ÷ 12  = -150 ÷ 12

x= -25/2  

Step-by-step explanation:

7 0
2 years ago
Jklm is a parallelogram find each measure
sammy [17]
The measure is one hundred eighty
4 0
3 years ago
standard automobile license plates in a country display 3 numbers, followed by 2 letters, followed by 2 numbers. how many differ
RoseWind [281]

The system of standard automotive license plates allows for a variety of standard plates is 39917124 ways.

<h3>Define the term permutation?</h3>
  • The number of potential arrangements for a given set is assessed mathematical terms, but this procedure is referred to as permutation.
  • The arrangement's order is essential when using permutations.

For the stated data;

Standard car license plates in a nation typically have 3 digits, 2 letters, and 2 numbers.

There are total 9 digits (0 - 9).

There are total 26 letter (A - Z)

Repetitions of letters and numbers given allowed.

Thus, numbers and the letters ca be arranged as;

1st place = 9 ways.

2nd place = 9 ways.

3nd place = 9 ways.

4th place = 26 ways.

6th place = 26 ways.

7th place = 9 ways.

8th place = 9 ways.

Total ways = 9×9×9×26×26×9×9

Total ways = 39917124

Thus, the system of standard automotive license plates allows for a variety of standard plates is 39917124 ways.

To know more about the permutation, here

brainly.com/question/1216161

#SPJ4

5 0
1 year ago
7/30+9/20 what is the answer pls hurry im so confused
Svetradugi [14.3K]

Here is your answer:

  • \frac{7}{30} + \frac{9}{20}
  • Find common denominator:
  • 30 \times 20 = 60 /20 \times 30 = 60
  • Common denominator is 60:
  • \frac{7}{30} + \frac{9}{20} = \frac{140}{60} + \frac{270}{60}
  • 140 + 270 = 410
  • = \frac{410}{60}
  • \frac{410}{60} \div 2 = \frac{205}{30} \div 5 = \frac{41}{6}
  • = \frac{41}{6} or 6\frac{5}{6}

Hope this helps!

8 0
3 years ago
Among 500 freshmen pursuing a business degree at a university, 311 are enrolled in an economics course, 243 are enrolled in a ma
Allushta [10]

Solution :

Let A = Economics, B = Mathematics

n(A) = 311, n(B) = 243, $n(A \cap B) = 135$

a). So, $n(A \cup B) = n(A) +n(B) - n(A \cap B)$

                     = 311 + 243 - 135

                     = 419

b). n(A only) = 311 - 135

                   = 176

     n(B only) = 243 - 135

                   = 108

Exactly one of these two courses

  $=\frac{176+108}{500}$

  = 0.568

c). Neither economics nor mathematics

    $=\frac{500-419}{500} $

  $=\frac{81}{500}$

 = 0.162

7 0
3 years ago
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