Answer:
C
Step-by-step explanation:
Using the rule of radicals/ exponents
⇔ ![\sqrt[n]{a^{m} }](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%20%7D)
Given
= ![\sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%7D)
→ C
You are to graph <span>y = |1.6x – 2| – 3.2. I trust you know that the graph of y=|x| is v-shaped, opening up, with vertex at (0,0).
Let's rewrite </span><span>y = |1.6x – 2| – 3.2 by factoring 1.6 out of |1.6x - 2|:
</span><span>y = 1.6*|x – 2/1.6| – 3.2
This tells us that the vertex of </span><span>y = |1.6x – 2| – 3.2 is at (2/1.6, -3.2). If you need an explanation of why this is, please ask.
Plot the vertex at (1.25, -3.2).
Find the y-intercept: Let x = 0 in </span><span>y = |1.6x – 2| – 3.2 and find y:
y = 2-3.2 = -1.2
The y-intercept is located at 0, -1.2)
Plot this y-intercept.
Now draw a straight line from the vertex to this y-intercept. Reflect that line across the y-axis to obtain the other half of the graph.</span>
Answer:
0.13 0.13 3.1.3
Step-by-step explanation:
Hope it's answer you plz mark as Brainlist
Answer:
B it is very simple my friend
Step-by-step explanation:
3.75 × 3.75 = 14.0
The correct answer is: [B]: "40 yd² " .
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First, find the area of the triangle:
The formula of the area of a triangle, "A":
A = (1/2) * b * h ;
in which: " A = area (in units 'squared') ; in our case, " yd² " ;
" b = base length" = 6 yd.
" h = perpendicular height" = "(4 yd + 4 yd)" = 8 yd.
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→ A = (1/2) * b * h = (1/2) * (6 yd) * (8 yd) = (1/2) * (6) * (8) * (yd²) ;
= " 24 yd² " .
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Now, find the area, "A", of the square:
The formula for the area, "A" of a square:
A = s² ;
in which: "A = area (in "units squared") ; in our case, " yd² " ;
"s = side length (since a 'square' has all FOUR (4) equal side lengths);
A = s² = (4 yd)² = 4² * yd² = "16 yd² "
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Now, we add the areas of BOTH the triangle AND the square:
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→ " 24 yd² + 16 yd² " ;
to get: " 40 yd² " ; which is: Answer choice: [B]: " 40 yd² " .
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