Note: Consider the side of first triangle is TQ instead of TA.
Given:
Triangles TQM and TPN which share vertex T.
To find:
The theorem which shows that .
Solution:
In triangle TQM and TPN,
[Given]
[Given]
[Given]
Since two sides and their including angle are congruent in both triangles, therefore both triangles are congruent by SAS postulate.
[SAS]
Therefore, the correct option is C.
So we have
h=hits
m=miss
h+m=10
gain 5 for every hit and lose 3 for every miss
so 5 times number of hit=points from hit
-3 times number of miss=points deducted from miss
add
5h-3m=18
so we have the equations
h+m=10
5h-3m=18
multiply first equation by 3
3h+3m=30
add to first equatio
3h+3m=30
<u>5h-3m=18 +</u>
8h+0m=48
8h=48
divide by 8
h=6
subsitute
h+m=10
6+m=10
subtract 6
m=4
6 hits
4 miss
<u />
X = 5 - y...so sub 5 - y in for x in the other equation
5(5 - y) - 4y = 7...distribute thru the parenthesis
25 - 5y - 4y = 7...simplify
25 - 9y = 7....subtract 25 from both sides
-9y = 7 - 25
-9y = - 18...divide both sides by -9
y = -18/-9
y = 2
x = 5 - y
x = 5 - 2
x = 3
solution is (3,2)
Answer:
Interquartile Range
Step-by-step explanation:
i think