Answer:
<em>The man paid $200 for the cow</em>
Step-by-step explanation:
<u>System of Equations</u>
Let's call:
x = price of the cow
y = price of the horse
The man bought the cow and the horse for $500, thus
x + y = 500 [1]
The cow was sold at a profit of 10%, thus:
Sale price of the cow= 1.1x
The horse was sold at a loss of 10%, thus:
Sale price of the horse= 0.9y
The total operation was a 2% loss, i.e. 0.98*500=490. Thus, we have:
1.1x + 0.9y = 490 [2]
From [1]:
y = 500 - x
Substituting in [2]:
1.1x + 0.9(500 - x) = 490
Operating:
1.1x + 450 - 0.9x = 490
0.2x = 490 - 450 = 40
x = 40/0.2
x = 200
The man paid $200 for the cow
Answer:
Adults =58, Students=92
Step-by-step explanation:
I got b I think that’s the answer
There is no solution ,<span>a+c=-10;b-c=15;a-2b+c=-5 </span>No solution System of Linear Equations entered : [1] 2a+c=-10
[2] b-c=15
[3] a-2b+c=-5
Equations Simplified or Rearranged :<span><span> [1] 2a + c = -10
</span><span> [2] - c + b = 15
</span><span> [3] a + c - 2b = -5
</span></span>Solve by Substitution :
// Solve equation [3] for the variable c
<span> [3] c = -a + 2b - 5
</span>
// Plug this in for variable c in equation [1]
<span><span> [1] 2a + (-a +2?-5) = -10
</span><span> [1] a = -5
</span></span>
// Plug this in for variable c in equation [2]
<span><span> [2] - (-? +2b-5) + b = 15
</span><span> [2] - b = 10
</span></span>
// Solve equation [2] for the variable ?
<span> [2] ? = b + 10
</span>
// Plug this in for variable ? in equation [1]
<span><span> [1] (? +10) = -5
</span><span> [1] 0 = -15 => NO solution
</span></span><span>No solution</span>
8.5x-6.1=-7.1
40x-6.1=-7.1
40x=-7.1+6.1
40x=-1
solution= x= -0.025
