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3 years ago

Please help me with this ASP

Mathematics

1 answer:

Mumz [18]3 years ago

6 0

Answer:

the first one

Step-by-step explanation:

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1.5k < 6 = ? Help me please.

Naily [24]

K<4
that should be the answer to your question

3 0

3 years ago

Read 2 more answers

A group of friends were working on a student film. They spent all their budget on props and costumes. They spent $693 on props,

sergeinik [125]

Answer:

The total budget is $1260

Step-by-step explanation:

Given

$Props = \$693$

$Costumes = 45\%$

Required

Determine the total budget

Since all budgets was spent on Props and Costumes only.

We have that.

$\%Props + \%Costumes = 100\%$

$\%Props + 45\%= 100\%$

$\%Props= 100\% -45\%$

$\%Props= 55\%$

In other words, 55% was spent on Props

Let the total budget be x, we have:

$55\% * x = \$693$

Make x the subject

$x = \$693/55\%$

$x = \$1260$

Hence, the total budget is $1260

5 0

2 years ago

Jessica works between 12h and 18h per week at her part-time job. She earns $9.25 per hour. The function p(h) = 9.25h models the

Tpy6a [65]

D. All real numbers between 111 and 166.5 inclusive.

3 0

3 years ago

Which phrase describes the linear relationship between the x and y values shown in the table?

kompoz [17]

9514 1404 393

Answer:

C. y is 6 less than x

Step-by-step explanation:

It is not hard to check.

A. 6 times x is 6×8 = 48, not 2

B. 6 times y is 6×2 = 12, not 8

C. 6 less than 8 is 2; 6 less than 9 is 3

D. 6 more than 8 is 14, not 2

The relation described in C matches the table.

5 0

2 years ago

Ericka decided to compare her observation to the average annual trend, which shows the water rising 1.8 mm/year. Remember, she u

Alex787 [66]

Answer with explanation:

Presume that, initial water level to be, 0 mm, at a time t=0.

And water level is rising at the rate of $1.8 \frac{\text{mm}}{\text{year}}$ .

After 6.2 years level of water will be =1.8 × 6.2

=11.16 mm

→Averge, that is increase in water level after 6.2 years is given by

$=\frac{W_{2}-W_{1}}{t_{2}-t_{1}}\\\\=\frac{11.16-0}{6.2-0}\\\\=\frac{11.16}{6.2}\\\\=1.8 \frac{\text{mm}}{\text{year}}$

→→Rate of Depreciating of water level is given by = Negative of Increase of water level= $-1.8 \frac{\text{mm}}{\text{year}}$

5 0

3 years ago

Read 2 more answers