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Answer:
<h3>A. </h3>- log
= log 3
- x³ log x = log 3
- 3x³ log x = 3 log 3
- x³ log x³ = log 3³
= 3³
- x³ = 3
- x =
- 4ˣ + 6ˣ = 9ˣ
- 2²ˣ + 2ˣ3ˣ = 3²ˣ
<u>Divide both sides by 2²ˣ</u>
- 1 + (3/2)ˣ = (3/2)²ˣ
<u>Substitute (3/2)ˣ = t</u>
- t² - t - 1 = 0
<u>Solve for t:</u>
- t = (1 ± √5)/2
<u>Positive root is considered as (3/2)ˣ can't be negative.</u>
- (3/2)ˣ = (1 + √5)/2
- x = log [(1 + √5)/2] / log (3/2)
- x = 1.18681439028
Answer:
a) The Venn diagram is presented in the attached image to this answer.
b) 0.82
c) 0.16
Step-by-step explanation:
a) The Venn diagram is presented in the attached image to this answer.
n(U) = 100%
n(S) = 48%
n(B) = 66%
n(H) = 38%
n(S n B) = 30%
n(B n H) = 22%
n(S n H) = 28%
n(S n B n H) = 12%
The specific breakdowns for each subgroup is calculated on the Venn diagram attached.
b) The probability that a randomly selected student likes basketball or hockey.
P(B U H)
From the Venn diagram,
n(B U H) = n(S' n B n H') + n(S' n B n H) + n(S n B n H') + n(S n B n H) + n(S n B' n H) + n(S' n B' n H) = 26 + 10 + 18 + 12 + 16 + 0 = 82%
P(B U H) = 82/100 = 0.82
c) The probability that a randomly selected student does not like any of these sports.
P(S' n B' n H')
n(S' n B' n H') = n(U) - [n(S' n B n H') + n(S' n B n H) + n(S n B n H') + n(S n B n H) + n(S n B' n H) + n(S' n B' n H) + n(S n B' n H')]
n(S' n B' n H') = 100 - (26 + 10 + 18 + 12 + 16 + 0 + 2) = 100 - 84 = 16%
P(S' n B' n H') = 16/100 = 0.16
