Answer:
we will fail to reject the null hypothesis and conclude that the mean pressure is not different from 4.7 psi
Step-by-step explanation:
Let's first define the hypothesis;
Null hypothesis: H0: μ = 4.7
Alternative hypothesis: Ha: μ ≠ 4.7
We have;
Sample size; n = 110
Sample mean; x¯ = 4.6
Variance: σ² = 0.64
Standard deviation; σ = √0.64 = 0.8
Formula for test statistic is;
z = (x¯ - μ)/(σ/√n)
z = (4.6 - 4.7)/(0.8/√110)
z = -0.1/0.0763
z = -1.31
From online p-value from z-score calculator attached, using; z = -1.31, two tailed hypothesis, significance value of 0.1, we have;
P-value = 0.190196
The p-value is greater than the significance value and thus we will fail to reject the null hypothesis and conclude that the mean pressure is not different from 4.7
σ μ
Answer:
12/7 hours
Step-by-step explanation:
First find the rate for hour for the two. For Lianne she can do 1/3 of the job per hour. For Julie she can do 1/4 of the job per hour.
Adding them together, 1/3+1/4= 7/12.
This 7/12 means that working together they can finish 7/12 of a job in an hour. We can use the speed*time=distance formula here and see that
7/12 * time = 1 job done
time = 12/7 hours.
<h2>
Answer:</h2>
Option: D is the correct answer.
D. (2,54)
<h2>
Step-by-step explanation:</h2>
We know that an outlier of a data set is the value that stands out of the rest of the data point i.e. either it is a too high value or a too low value as compared to other data points.
Here we are given a set of data points as:
(2,54)
(4,7)
(6, 9)
(8,12)
(10,15)
Hence, we see that the output values i.e. 7 in (4,7) ; 9 in (6,9) ; 12 in (8,12) and 15 in (10,15) are closely related.
Hence, the data point that is an outlier is:
(2,54)
(As 54 is a much high value as compared to other)
Let
x--------> number of dogs that completed the obedience class
we know that
total number of dogs=5
<span>Eighty percent of the dogs have completed obedience classes
so
x=0.80*5------> x=4
the answer is
4 dogs </span>have completed obedience classes
