16y^3 + 9x^2y - 54x = 0
16*3y* dy/dx + 9x^2* dy/dx + 18xy - 54 = 0
dy/dx = = (54 - 18xy) / (48y + 9x^2)
I have to go I can do the second part later
The anwser to your question is 1 and 5/7
Problem 3
<h3>Answer: 1/5 of a gallon per minute</h3>
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Explanation:
Two points from the graph are (10,2) and (20,4)
Apply the slope formula
m = (y2-y1)/(x2-x1)
m = (4-2)/(20-10)
m = 2/10
m = 1/5
The slope of the graph is 1/5.
Do the same for two points from the table. I'll use the first two rows
m = (y2-y1)/(x2-x1)
m = (4-2)/(10-5)
m = 2/5
The slope of the table is 2/5.
Subtract the two slopes to wrap things up:
2/5 - 1/5 = (2-1)/5 = 1/5
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Problem 5
<h3>Answer:
23 degrees</h3>
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Explanation:
Angles 1 and 3 are same side exterior angles, so they are supplementary due to the parallel lines set up here.
(angle1)+(angle3) = 180
(157) + (angle3) = 180
angle3 = 180-157
angle3 = 23 degrees
Answer:
18
Step-by-step explanation:
The hypotenuse (longest side) = The 2 sides added together.
