The first company charges $40 per backpack and a $10 shipping fee for the order and the second company charges $38 per backpack
2 answers:
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Answer:
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?
90th percentile
The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Answer:
13
Step-by-step explanation:
The computation of the number of people in the chorus are 50 or older is as follows
According to the attached figure
In the age of 50 - 60 , there is 8 people
In the age of 60 - 70 , there is 4 people
In the age of 70 -80, there is 1 people
So, if we do the total that comes
= 8 people + 4 people + 1 people
= 13 people
Hence, the no of people would be 13
The same is relevant
Answer:
Step-by-step explanation:
