Question

Which of the following are the coordinates of vertices of the following square centered at the Origin, with side length b?

Answer 1

Answer:

Option (3) is correct.

coordinate of given  square centered at the Origin, with side length b is W$(\frac{b}{2},\frac{b}{2})$, S$(\frac{-b}{2},\frac{b}{2})$, T$(\frac{-b}{2},\frac{-b}{2})$ and Z$(\frac{b}{2},\frac{b}{2})$.

Step-by-step explanation:

Given a square centered at the Origin, with side length b.

We have to find the coordinates of vertices of the square.

Since, the given square is centered at origin (0,0) and length of side is b then x and y axis divide each side in equal part.

Thus, each coordinate of square is $\frac{b}{2}$.

Since, we know in first quadrant both x and y are positive thus, point W has coordinate $(\frac{b}{2},\frac{b}{2})$

Also in second quadrant x is negative and y is positive thus, point S has coordinate $(\frac{-b}{2},\frac{b}{2})$

in third quadrant both x and y is negative thus, point T has coordinate $(\frac{-b}{2},\frac{-b}{2})$

in fourth  quadrant y is negative and x is positive thus, point Z has coordinate $(\frac{b}{2},\frac{b}{2})$

Thus, coordinate of given  square centered at the Origin, with side length b is W$(\frac{b}{2},\frac{b}{2})$, S$(\frac{-b}{2},\frac{b}{2})$, T$(\frac{-b}{2},\frac{-b}{2})$ and Z$(\frac{b}{2},\frac{b}{2})$.

Thus, option (3) is correct.