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Black_prince [1.1K]
3 years ago
15

Please help

Mathematics
1 answer:
Alinara [238K]3 years ago
7 0

Answer: A. 2x(x²)+2x(5x)+2x(-2xy)+2x(-10y)

B. 2x(x²+5x-2xy-10y)

Step-by-step explanation:

note: x*x means x times x

remember distributive and reverse it

ab+ac=a(b+c)

a is gcf

factor each

2x³=2*x*x*x

10x²=2*5*x*x

4x²y=2*2*x*x*y

20xy=2*2*5*x*y

gcf=2*x or 2x

2x³+10x²-4x²y-20xy=

2x(x²)+2x(5x)+2x(-2xy)+2x(-10y)=

2x(x²+5x-2xy-10y)

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SIZIF [17.4K]

Option E

The sum of all possible values of y is 20

<em><u>Solution:</u></em>

Given that,

6x + 2y = 25

Where, xy > 0

We have to find the sum of all possible values of y if x is a positive integer

We can use values of x = 1, 2, 3, 4

For x = 5 and above, y will be negative

<em><u>Substitute x = 1 in given equation</u></em>

6(1) + 2y = 25

6 + 2y = 25

2y = 25 - 6

2y = 19

Divide both the sides of equation by 2

y = \frac{19}{2}

<em><u>Substitute x = 2 in given equation</u></em>

6(2) + 2y = 25

2y = 25 - 12

2y = 13

Divide both the sides of equation by 2

y = \frac{13}{2}

<em><u>Substitute x = 3 in given equation</u></em>

6(3) + 2y = 25

2y = 25 - 18

2y = 7

Divide both the sides of equation by 2

y = \frac{7}{2}

<u><em>Substitute x = 4 in given equation</em></u>

6(4) + 2y = 25

24 + 2y = 25

2y = 25 - 24

2y = 1

Divide both the sides of equation by 2

y = \frac{1}{2}

<u><em>Now add all the values of "y"</em></u>

\text{Sum of possible values of y } = \frac{19}{2} + \frac{13}{2} + \frac{7}{2} + \frac{1}{2}\\\\\text{Sum of possible values of y } = \frac{19+13+7+1}{2}\\\\\text{Sum of possible values of y } = \frac{40}{2}=20

Thus sum of all possible values of y is 20

3 0
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