Answer:
A. 5s+2
B. 8s+8
C. 75
D. 27
Step-by-step explanation:
Is difficult to read the exact expressions. If a mistake is present then fix the number and use the same method.
A. The perimeter of the square is all 4 equal sides added together. The length of a side is . Since there are four sides then:
Adding 1/4+1/4+1/4+1/4=1. This applies here leaving 5s+2 as the answer.
B. The perimeter of the rectangle is all four sides added together. A rectangle has two pairs of equal side so P = 2l+2w.
C. If s=5 then the sum of the two perimeters is:
5s+2+8s+8
5(5)+2+8(5)+8
25+2+40+8
75
D. Subtract the two perimeters by computing s=7:
8s+8 -(5s+2)
8s+8-5s-2
8(7)+8-5(7)-2
56+8-35-2
64-35-2
29-2
27
The first term is 2
Therefor t₁ = 2
Each aditional term is 5 times the previous term
That's the second choice
u nice keep goin.
sry lol