Answer:
C) 5 3√2
Step-by-step explanation:
To solve, set an equation:
First Number: x
Second Number: 2x
x+2x=36
3x=36
divide both sides by 3
x=13
First Number: (x) 12
Second Number: (2x) 24
Answers: 12 and 24
How many distinct products can be formed using two different integers from the given set: {–6, –5, –4, –3, –2, –1, 0, 1, 2, 3, 4
zhannawk [14.2K]
Number of distinct products that can be formed is 144
<h3>Permutation</h3>
Since we need to multiply two different integers to be selected from the set which contains a total of 12 integers. This is a permutation problem since we require distinct integers.
Now, for the first integer to be selected for the product, since we have 12 integers, it is to be arranged in 1 way. So, the permutation is ¹²P₁ = 12
For the second integer, we also have 12 integers to choose from to be arranged in 1 way. So, the permutation is ¹²P₁ = 12.
<h3>
Number of distinct products</h3>
So, the number of distinct products that can be formed from these two integers are ¹²P₁ × ¹²P₁ = 12 × 12 = 144
So, the number of distinct products that can be formed is 144
Learn more about permutation here:
brainly.com/question/25925367
Answer:
I am pretty sure it is when you have a sequence of numbers that you are subtracting or adding from by the same constant over and over
Step-by-step explanation:
an=a1+(n-1)d
d=common difference
an= the nth term in the sequence
a1 first term in the sequence. (Usually you can plug in 1, as the n, and work from there)
