For No. 13 you need to calculate the distance each girl travels and compare to see whose distance is greater. The formula for distance is rate x time or d=rt. The rate is just how fast they consistently go.
Mia
d = r x t
d = 14 x 3/2
d = 21 miles
Chloe
d = r x t
d = 35 x 3/4 (btw 3/4 is just 45/60 simplified)
d = 105/4 = 26 1/4 miles
Final Answer: Chloe traveled further
For No. 14 we will recalculate Mia's distance but replace 1/5 hours with 2 hours because it says she will bike 30 minutes after Chloe had stopped. Afterwards we will compare Mia's new distance with Chloe's old distance.
Mia
d = r x t
d = 14 x 2
d = 28 miles
Final Answer: Yes Mia would be able to catch up to Chloe, and even surpass her in 30 minutes if Chloe stopped.
First 4/7 times 7/11 and plus 5,the result of 4/7 times 7/11 equal 4/11,AND THEN 4/11 PLUS 5 EQUAL 5 AND 4/11
Answer:
94.2
Step-by-step explanation:
google and simple addition
Answer:
M = 1/0.000121 = 8264.5 years
Step-by-step explanation:
M = − k ∫∞₀ teᵏᵗdt
To obtain this mean life, we'll use integration by parts to integrate the function ∫ teᵏᵗdt
∫udv = uv - ∫ vdu
u = t
du/dt = 1
du = dt
∫ dv = ∫ eᵏᵗdt
v = eᵏᵗ/k
∫udv = ∫ teᵏᵗdt
uv = teᵏᵗ/k
∫ vdu = eᵏᵗ/k
∫ teᵏᵗdt = (teᵏᵗ/k) - ∫eᵏᵗ/k
But, ∫eᵏᵗ/k = (1/k) ∫eᵏᵗ = (1/k²) eᵏᵗ = eᵏᵗ/k²
∫ teᵏᵗdt = (teᵏᵗ/k) - eᵏᵗ/k²
The rest of the calculation is done on paper in the image attached to this question
