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3 years ago

Help Please Right now

Mathematics

1 answer:

jek_recluse [69]3 years ago

8 0

Answer:

150

Step-by-step explanation:

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Question 3 of 10

Leya [2.2K]

The third quartile of this data set is B. 24.

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3 years ago

Please help with this geometry question!

faltersainse [42]

Since the properties of a rhombus tells us that both pairs of opposite sides are congruent we can therefore conclude that DB will be 12

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3 years ago

When you find the<br> median of a set of data,<br> what quartile would this<br> number be?

IgorC [24]

I think your question isn’t phrased well

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4 years ago

Please help me with this problem

Naya [18.7K]

Answer:

Dasha has 52 roses

Step-by-step explanation:

Rewrite the first sentence in an equation: (D= Dasha) (A= Anna)

D=4A

Rewrite the second sentence in an equation:

A+39=D

1) Substitute A+39 as D in the first equation:

A+39=4A

2) Subtract A from both sides:

3A=39

3) Divide both sides by 3:

A=13

4) Now substitute 13 as A in the second equation:

13+39=D

5) Solve:

D=52

4 0

3 years ago

seven different gifts are to be distributed among 10 children. How many distinct results are possible if no child is to receive

Alik [6]

Answer:

120 distinct results are possible if no child is to receive more than one gifts.

Step-by-step explanation:

When the order is not important, we use the combination formula:

$C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The order is said to be not important if for example, John receiving the Buffalo Bills jersey and then Laura receiving the Cleveland Browns jersey is the same as Laura receiving the Cleveland Browns jersey before John receives the Buffalo Bills jersey.

In this problem, we have that:

Combinations of 7 from a set of 10 elements. So

$C_{n,x} = \frac{n!}{x!(n-x)!}$

$C_{10,7} = \frac{10!}{7!(3)!} = 120$

120 distinct results are possible if no child is to receive more than one gifts.

6 0

3 years ago