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butalik [34]
3 years ago
5

Yo i need the answer

Mathematics
1 answer:
klemol [59]3 years ago
5 0

Answer:

c

Step-by-step explanation:

im pretty sure an additive inverse is just the absolute value

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What is the domain of the function shown in the graph below?
Maksim231197 [3]

Answer:

Domain: (+∞, -∞)

Step-by-step explanation:

Domain = x value

hope it helps

6 0
3 years ago
Max spent 11 dollars on items. He bought milk, eggs and fabric softener. The eggs cost one fifth of what the milk cost and the f
LiRa [457]
M + e + f = 11
e = 1/5m
f = 3m

m + 1/5m + 3m = 11 <== ur equation
5/5m + 1/5m + 15/5m = 11
21/5m = 11
m = 11 / (21/5)
m = 11 * 5/21
m = 55/21
m = 2.619 rounds to 2.62...milk

e = 1/5m
e = 1/5(2.62)
e = 0.53 .....eggs

f = 3m
f = 3(2.62)
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4 0
3 years ago
Read 2 more answers
A military cannon is placed at the base of a hill. The cannon is fired at an angle toward the hill. The path
katrin [286]

Answer:

Algebracicaly speaking the answer would be either -13.3876 or - 158.612 through the quadratic equation, but these answers don’t make sense in this real world scenario.

Step-by-step explanation:

7 0
2 years ago
Which relation is a function? Graph with 5 points plotted at (negative 3, 2), (negative 2, 2), (negative 1, 2), (negative 2, neg
Olenka [21]

Answer:


use the verticle line test. if a verticle line touches two points on the graph then it is not a function, if the verticle line only touches one point then it is a function.

for your question the answer is the 3rd option - Graph with 5 points plotted at (negative 3, 2), (negative 2, negative 1), (0, 3), (1, 0), and (2, negative 3)


3 0
3 years ago
The sides OP and RO of triangle POR are produced to points S and T respectively. If ∠SPR = 145° and ∠POT = 115° , find ∠PRO
Margarita [4]

Answer:

\angle PRQ = 80

Step-by-step explanation:

Given

\angle SPR = 145^o

\angle POT = 115^o

See attachment

Required

Find \angle PRO

First, calculate \angle RPO

\angle RPO + \angle SPR = 180 --- angle on a straight line

So, we have:

\angle RPO + 145 = 180

Collect like terms

\angle RPO = 180 - 145

\angle RPO = 35

Next, calculate PQR

\angle POR + \angle POT = 180

So, we have:

\angle POR + 115 = 180

Collect like terms

\angle POR = 180-115

\angle POR = 65

So, PRO is calculated as:

\angle PRO + \angle POR + \angle RPO = 180 --- angles in a triangle

So, we have:

\angle PRO + 65 + 35= 180

\angle PRO + 100= 180

Collect like terms

\angle PRO = 180-100

\angle PRO = 80

3 0
3 years ago
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