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mihalych1998 [28]
2 years ago
13

Which fraction is equivalent to g? 24 4 o 40

Mathematics
1 answer:
Gennadij [26K]2 years ago
7 0

Answer:

vtvgjvvuctucytcuyvuyvuy

Step-by-step explanation:

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Plane R contains which of the following?
mars1129 [50]

The letter R is on the yellow section, which indicates the yellow area is plane R.

Now see what points and lines are on the yellow sections.

Point M, point R, line F are all in the yellow area. Point X and Y are at the intersection of the two planes, so could be part of both.

Based on the provided answers, the answer would be: Point M and line f.

4 0
3 years ago
Simpl following 12mn+4m²n-3mn+2m²n​
almond37 [142]

Answer:

9m+6m^2n

Step-by-step explanation:

12mn-3mn=9mn

4m^2n+2m^2n=6m^2n

==> 9m+6m^2n

or rewrite as 3m(3+2mn)

5 0
3 years ago
Read 2 more answers
Look at the function f(x) = x3 - 4 x. which describes an interval in which the function is increasing?
Bad White [126]
Differentiate it
 get  f ' (x)=3x^2-4
put 3x^2-4=0
x=2/√3,-2/√3
so interval 
x∈(-2/√3,2/√3)
5 0
3 years ago
Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0
2 years ago
What is 285.39154 rounded to the nearest hundredth
svp [43]
285.39 I belive the awsner is
3 0
3 years ago
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