Answer:
160/196
Step-by-step explanation:
it would be easier if you converted all fractions to improper fractions
so 3 1/5 would equal 16/5 and 2 4/5 would equal to 14/5
: to solve this you would need the same common denomenator,
to do this you can multiply 5 and 3 by something to make the lowest common denominator, which would be 15
thus
multiplying first fraction by 3 and the second by 5
42/15 - 10/15 = 32/15
now 32/15 divided by 14/5
the rule for dividing fractions, is flipping the fraction which you will be using to divide, and then multiplying it to the first fraction:
multiplied by ![\frac{5}{14}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B14%7D)
thus, answer is 160/196
Answer:
A. 7 in.
Step-by-step explanation:
We have been given that the perimeter of a rectangle is 16 inches. The equation that represents the perimeter of the rectangle is , where l represents the length of the rectangle and w represents the width of the rectangle.
We know that perimeter of rectangle is 2 times the sum of width and length of rectangle.
![\text{Perimeter}=2(l+w)](https://tex.z-dn.net/?f=%5Ctext%7BPerimeter%7D%3D2%28l%2Bw%29)
![\text{16 in}=2(l+w)](https://tex.z-dn.net/?f=%5Ctext%7B16%20in%7D%3D2%28l%2Bw%29)
![\frac{\text{16 in}}{2}=\frac{2(l+w)}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7B16%20in%7D%7D%7B2%7D%3D%5Cfrac%7B2%28l%2Bw%29%7D%7B2%7D)
![\text{8 in}=l+w](https://tex.z-dn.net/?f=%5Ctext%7B8%20in%7D%3Dl%2Bw)
To be a rectangle length cannot be 8 as length and width of the rectangle is 8 inches.
Therefore, 7 inches the possible value for the length of the rectangle.
Answer:
D, E, F, C,
Step-by-step explanation:
Answer:
A, D, E
Step-by-step explanation:
Time is a function of temperature because there are no points where the x-value has more than one y-value.
There are two points where the temperature reaches 74 degrees.
Between 5 and 9 the temperature did not change.
Answer:
<h2>84, 42</h2>
Step-by-step explanation:
![x,\ y-numbers\\\\\text{The system of equations:}\\\\\underline{+\left\{\begin{array}{ccc}x+y=126\\x-y=42\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad2x=168\qquad\text{divide both sides by 2}\\.\qquad x=84\\\\\\\text{Put the value of}\ x\ \text{to the first equation:}\\\\84+y=126\qquad\text{subtract 84 from both sides}\\y=42](https://tex.z-dn.net/?f=x%2C%5C%20y-numbers%5C%5C%5C%5C%5Ctext%7BThe%20system%20of%20equations%3A%7D%5C%5C%5C%5C%5Cunderline%7B%2B%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7Dx%2By%3D126%5C%5Cx-y%3D42%5Cend%7Barray%7D%5Cright%7D%5Cqquad%5Ctext%7Badd%20both%20sides%20of%20the%20equations%7D%5C%5C.%5Cqquad2x%3D168%5Cqquad%5Ctext%7Bdivide%20both%20sides%20by%202%7D%5C%5C.%5Cqquad%20x%3D84%5C%5C%5C%5C%5C%5C%5Ctext%7BPut%20the%20value%20of%7D%5C%20x%5C%20%5Ctext%7Bto%20the%20first%20equation%3A%7D%5C%5C%5C%5C84%2By%3D126%5Cqquad%5Ctext%7Bsubtract%2084%20from%20both%20sides%7D%5C%5Cy%3D42)