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TiliK225 [7]
3 years ago
7

the entry fee to the fair is 4.00 . each rides requires a ticket that cost 0.50 heidi spent a total 12.00 how many ticket did he

idi purchase
Mathematics
1 answer:
Fofino [41]3 years ago
3 0
She bought 16 tickets
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14/100 in simplest form
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0.14. hope this helps
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Jennifer has 25 coins with a total value of $4.25. The coins are quarters and nickels. How many of each does she have?
kirill115 [55]

Answer:

15 quarters, 10 nickels

Step-by-step explanation:

q+n=25

0.25q+0.05n=4.25

multiply the first equation by -0.25 and add the second equation to it

-0.25q-0.25n=-6.25\\0.25q+0.05n=4.25
________________
                -0.2n=-2

n=\frac{-2}{-0.2} =10   has 10 nickels

q=25-n=25-10=15  has 15 quarters

10(.05) +15(0.25) = 0.5 + 3.75 = 4.25

Hope this helps

8 0
11 months ago
Limit question thing plz help me
Sphinxa [80]

Answer:

The limit does not exist

Step-by-step explanation

For this question you have to look at the function and see what y value does it approach as it gets closer and closer to x =2, from the left side it looks like it approaces 4 and from the left side it looks like it's approaching 1, since the limits from the left and right sides are not the same, the limit does not exist

5 0
3 years ago
A SPHERICAL BALL HAS A DIAMETER OF 8 INCHES.THE BALL HAS A SLOW LEAK IN WHICH AIR ESCAPES AT THE RATE OF 2.5 CUBIC INCHES PER SE
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107.52 seconds for the ball to deflate.
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3 years ago
Find the approximate area between the curve f(x) = -4x² + 32x and on the x-axis on the interval [0,8] using 4 rectangles. Use th
Doss [256]

Split up the interval [0, 8] into 4 equally spaced subintervals:

[0, 2], [2, 4], [4, 6], [6, 8]

Take the right endpoints, which form the arithmetic sequence

r_i=2+\dfrac{8-0}4(i-1)=2i

where 1 ≤ <em>i</em> ≤ 4.

Find the values of the function at these endpoints:

f(r_i)=-4{r_i}^2+32r_i=-16i^2+64i

The area is given approximately by the Riemann sum,

\displaystyle\int_0^8f(x)\,\mathrm dx\approx\sum_{i=1}^4f(r_i)\Delta x_i

where \Delta x_i=\frac{8-0}4=2; so the area is approximately

\displaystyle2\sum_{i=1}^4(-16i^2+64i)=-32\sum_{i=1}^4i^2+128\sum_{i=1}^4i=-32\cdot\frac{4\cdot5\cdot9}6+128\cdot\frac{4\cdot5}2=\boxed{320}

where we use the formulas,

\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2

\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6

6 0
3 years ago
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