X² + 6x -12 = 0
x = <u>-(6) +/- √((6)² - 4(1)(-12))</u>
2(1)
x = <u>-6 +/- √(36 + 48)</u>
2
x = <u>-6 +/- √(84)
</u> 2<u>
</u>x = <u>-6 +/- 2√(21)
</u> 2<u>
</u>x = -3 <u>+</u> √(21)
x = -3 + √(21) x = -3 - √(21)
Answer:
see explanation
Step-by-step explanation:
Given
2x + 7y = 42
To find the x- intercept let y = 0 in the equation and solve for x
2x + 7(0) = 42, that is
2x = 42 ( divide both sides by 2 )
x = 21 ← x- intercept or (21, 0 )
To find the y- intercept let x = 0 in the equation and solve for y
2(0) + 7y = 42 , that is
7y = 42 ( divide both sides by 7 )
y = 6 ← y- intercept or (0, 6 )
Answer:
x = 5
Step-by-step explanation:
Given
f(x) = - 3x + 21 and f(x) = 6, then equating gives
- 3x + 21 = 6 ( subtract 21 from both sides )
- 3x = - 15 ( divide both sides by - 3 )
x = 5
