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3 years ago

If sin f° = eight ninths and the measure of segment YW is 24 units, what is the measure of segment YX?

Mathematics

1 answer:

labwork [276]3 years ago

8 0

Answer:

Step-by-step explanation:

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WILL GIVE BRAINLIEST AND 30 POINTS!

Katena32 [7]

Answer:

$2x\sqrt{10}-2x\sqrt 5$

Step-by-step explanation:

$\sqrt{5x} (\sqrt{8x^2}-2\sqrt{x})\\\mathrm{Multiply \: parentheses \: by \sqrt{5x}}\\=\sqrt{5x \times 8x^2}-2\sqrt{5x \times x}\\=x\sqrt {4\times 10 x}-2x\sqrt{5}\\=2x\sqrt{10}-2x\sqrt{5}$

6 0

3 years ago

Can someone please help me with this? I'll mark brainliest for the right answer

lapo4ka [179]

Where’s the question?

6 0

3 years ago

Question 6(Multiple Choice Worth 1 points) (02.05 MC) Choose the table that represents g(x) = 4⋅f(x) when f(x) = x − 5. x g(x) 1

RSB [31]

Answer: (b)

x g(x)

1 -16

2 -12

3 -8

If g(x) is 4*f(x), then we can find g(x) by multiplying 4 by x-5

g(x) = 4(x-5)

= 4x-20

Now we can plug in 1,2, and 3 for x to see which table makes sense.

g(1) = 4(1) - 20

= -16

g(2) = 4(2) - 20

= -12

g(3) = 4(3) - 20

= -8

hope this helps

4 0

4 years ago

The radius of a spherical balloon is measured as 20 inches, with a possible error of 0.03 inch. Use differentials to approximate

soldi70 [24.7K]

Answer:

a) $V = 33510.322\,in^{3}$ , b) $A_{s} = 5026.548\,in^{2}$ , c) $\% V = 0.450\,\%$ , $\%A_{s} = 0.300\,\%$ .

Step-by-step explanation:

The volume and the surface area of the sphere are, respectively:

$V = \frac{4}{3}\pi \cdot r^{3}$

$A_{s} = 4\pi \cdot r^{2}$

a) The volume of the sphere is:

$V = \frac{4}{3}\pi \cdot (20\,in)^{3}$

$V = 33510.322\,in^{3}$

b) The surface area of the sphere is:

$A_{s} = 4\pi \cdot (20\,in)^{2}$

$A_{s} = 5026.548\,in^{2}$

c) The total differentials for volume and surface area of the sphere are, respectively:

$\Delta V = 4\pi\cdot r^{2}\,\Delta r$

$\Delta V = 4\pi \cdot (20\,in)^{2}\cdot (0.03\,in)$

$\Delta V = 150.796\,in^{3}$

$\Delta A_{s} = 8\pi\cdot r \,\Delta r$

$\Delta A_{s} = 8\pi \cdot (20\,in)\cdot (0.03\,in)$

$\Delta A_{s} = 15.080\,in^{2}$

Relative errors are presented hereafter:

$\%V = \frac{\Delta V}{V}\times 100\%$

$\%V = \frac{150.796 \,in^{3}}{33510.322\,in^{3}}\times 100\,\%$

$\% V = 0.450\,\%$

$\% A_{s} = \frac{\Delta A_{s}}{A_{s}}\times 100\,\%$

$\% A_{s} = \frac{15.080\,in^{2}}{5026.548\,in^{2}}\times 100\,\%$

$\%A_{s} = 0.300\,\%$

4 0

3 years ago

Plss help me... with explanation<br>(20 pnts)

ASHA 777 [7]

Answer:

B. slope

Step-by-step explanation:

5 0

3 years ago