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nadya68 [22]
2 years ago
9

Hank is throwing a surprise party. The party costs $20 per person. Create an equation and graph to represent the relationship be

tween the cost of the party and the number of friends attending.
Complete the following table:

Number of friends (f) 5 10 15 20
Cost of party (c) 100 200 300 400

Plots the points from the table onto the graph.
Mathematics
1 answer:
o-na [289]2 years ago
3 0

Answer: Answer with Step-by-step explanation:

Since we have given that

Cost of party per person = $20.

Let the number of friends be 'f'.

Let the cost of party be 'p'.

According to question, our equation becomes

p= 2f

So, if p = 100, then f = p/2 = 100/2 = 50 if f = 10, then, p = 2f = 2 • 10 = 20 If p = 300 then, f = 300/2 = 150, If f = 20, then, p = 2f = 2 • 20 = 40 So, Table as follows:

Number of friends cost of party

50 100

10 20

150 300

20 40

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It would help if we represent the information in form of two-ways table as shown below 

The number of students who are not on probation is 104 students
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3 years ago
A group of students entered the museum at 3:30 pm and came out at 5:15. how long were they in the museum ?
aksik [14]

Answer:

1 hour and 45 minutes

Hope this helped, have a nice day! :)

8 0
3 years ago
A special deck of cards has ten cards. Four are green (G), four are blue (B), and two are red (R). When a card is picked, the co
a_sh-v [17]

Answer:

{GT, GH, BT, BH, RT, RH};

1 /5;

Mutually exclusive ;

Not mutually exclusive.

Step-by-step explanation:

Given :

Green cards, G = 4

Blue cards, B = 4

Red cards, R = 2

For a coin toss :

{H, T}

A card is picked, then a coin is tossed :

Sample space :

{GT, GH, BT, BH, RT, RH}

2.) probability of picking a green card, then probability of landing a head on a coin toss

P(A) = number of required outcome / Total possible outcomes

P(A) = P(green card) * P(Head)

P(A) = (4 / 10) * (1/2)

P(A) = 4 /20

P(A) = 1/5

C.)

Both A and B are mutually exclusive, since both event A and event B cannot occur together, since both red and green cannot be picked during a single pick, this either a red is picked or green is picked, then they are A and B are mutually exclusive.

D.) Event A and C are not mutually exclusive, picking a green card, event A and picking a red or blue card, event B. Both event can happen simultaneously, hence, event A and B are not mutually exclusive.

6 0
3 years ago
Candy Crunchers wants to see if their new candy is enjoyed more by high school or middle school students. They decide to visit o
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The sample % of these two populations would be 100/size (of student body at each school) x 100 so this would compare the two student bodies preferences for the particular type of candy bar. However, the actual % of the whole student body at each school would be a factor also. If the high school only had 200 students then this would be 50% representative but if the middle school had say 500 students this would only be 20% representative so this would have to be taken into account too. It might be more representative to have the same % of the student bodies respectively for the sample. 
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3 years ago
What ordered pair is a solution of the equation?<br><br> y=-2x-5
ioda

\sf \underline{Answer:}

Pick any value for x, like x = 0, plug it into the equation, and get the value for y. For x = 0,

2(0) + y = 5

y = 5

The ordered pair is (0,5). Find other ordered pairs using the same reasoning.

3 0
1 year ago
Read 2 more answers
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