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nadya68 [22]
2 years ago
9

Hank is throwing a surprise party. The party costs $20 per person. Create an equation and graph to represent the relationship be

tween the cost of the party and the number of friends attending.
Complete the following table:

Number of friends (f) 5 10 15 20
Cost of party (c) 100 200 300 400

Plots the points from the table onto the graph.
Mathematics
1 answer:
o-na [289]2 years ago
3 0

Answer: Answer with Step-by-step explanation:

Since we have given that

Cost of party per person = $20.

Let the number of friends be 'f'.

Let the cost of party be 'p'.

According to question, our equation becomes

p= 2f

So, if p = 100, then f = p/2 = 100/2 = 50 if f = 10, then, p = 2f = 2 • 10 = 20 If p = 300 then, f = 300/2 = 150, If f = 20, then, p = 2f = 2 • 20 = 40 So, Table as follows:

Number of friends cost of party

50 100

10 20

150 300

20 40

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The estimate of the population proportion should be within plus or minus 0.02, with a 90% level of confidence. The best estimate
Rudiy27

Answer:

The sample size required is 910.

Step-by-step explanation:

The confidence interval for population proportion is:

CI=\hat p\pm z_{ \alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }

The margin of error is:

MOE=z_{ \alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }

Given:

\hat p = 0.16\\MOE= 0.02\\Confidence\ level =0.90

The critical value of <em>z</em> for 90% confidence level is:

z_{\alpha /2}=z_{0.10/2}=z_{0.05}=1.645 *Use a standard normal table.

Compute the sample size required as follows:

MOE=z_{ \alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }\\0.02=1.645\times \sqrt{\frac{0.16(1-0.16)}{n} }\\n=\frac{(1.645)^{2}\times 0.16\times (1-0.16)}{(0.02)^{2}} \\=909.2244\\\approx910

Thus, the sample size required is 910.

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3 years ago
Can someone help me, please
shepuryov [24]

Answer:

yes... 13.3

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Since all angles in a triangle add up to 180°, we have:

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The answer is -8

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