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3 years ago

PLEASE HELP PLEASEEEEEE

Mathematics

1 answer:

svet-max [94.6K]3 years ago

6 0

Step-by-step explanation:

Volume =

1/3πr²h

= 1/3×3.14×2²×9

= 37.68 units ³

Hope it will help :)❤

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Trevon, Leah, and Beth are playing a computer game. Trevon scores -8. Beth’s score was 3/4 of trevons score, and Leah’s score wa

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-8 = trevon

(3/4)-8 = beth
= -6

1/4[(3/4)-8] = leah
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Answer:

a. 0.1647;
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Step-by-step explanation:

By definition, if two event $A$ and $B$ are independent, then

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Since the outcome of these two events are independent,

$\begin{aligned}P(\texttt{Jane} \cap \texttt{Joe}) &= P(\texttt{Jane}) \cdot P(\texttt{Joe})\\ &= 0.61 \times 0.27 \\&= 0.1647\end{aligned}$ .

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$P(\texttt{Jane}^{\prime}) = 1 - P(\texttt{Jane}) = 1- 0.61 = 0.39$ .

$P(\texttt{Joe}^{\prime}) = 1 - P(\texttt{Joe}) = 1- 0.27 = 0.73$ .

Since the two events $\texttt{Jane}$ and $\texttt{Joe}$ , $\texttt{Jane}^{\prime}$ and $\texttt{Joe}^{\prime}$ are also independent. Probability that neither professor got funded:

$P(\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime}) = P(\texttt{Jane}^{\prime}) \cdot P(\texttt{Joe}^{\prime}) = 0.39 \times 0.73 = 0.2847$ .

Probability that at least one professor got funded- in other words, it is not true that neither professor got funded:

$P((\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime})^{\prime}) = 1- P(\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime}) = 0.7153$ .

Similarly, since the two events $\texttt{Jane}$ and $\texttt{Joe}$ , $\texttt{Jane}$ and $\texttt{Joe}^{\prime}$ are also independent. Probability that Jane but not Joe got funded:

$P(\texttt{Jane} \cap (\texttt{Joe}^{\prime})) = P(\texttt{Jane}) \cdot P(\texttt{Joe}^{\prime}) = 0.61 \times 0.73 = 0.4453$ .

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3 years ago

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Mandarinka [93]

Answer:

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Answer:

B 3x+2

Step-by-step explanation:

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P=2(L+W)

if x=width then

P=2(L+x)

P=8x+8

hmm

8x+8=2(L+x)

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Answer:

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