Answer:
answer is d if its wrong i am sorry
The answer is 200 pounds
Let x be the number of pounds of the second chocolate that should be added
First chocolate: 300 pounds
cocoa to caramel = 1 to 7
So, there are in total 8 parts (1 + 7 = 8)
There is:
Cocoa: 1/8 * 300 pounds
Caramel: 7/8 * 300 pounds
Second chocolate: x pounds
cocoa to caramel = 1 to 15
So, there are in total 16 parts (1 + 15 = 16)
There is:
Cocoa: 1/16 * x pounds
Caramel: 15/16 * x pounds
Resulting chocolate: 300 + x pounds
cocoa to caramel = 1 to 9
So, there are in total 10 parts (1 + 9 = 10)
There is:
Cocoa: 1/10 * (300 + x) pounds
Caramel: 9/10 * (300 + x) pounds
Since in all chocolate, there is only one part of cocoa, it is easy to add up the amounts of cocoa:
1/8 * 300 + 1/16 * x = 1/10 * (300 + x)
300/8 + x/16 = 300/10 + x/10
75/2 + x/16 = 30 + x/10
75/2 - 30 = x/10 - x/16
75/2 - 60/2 = 8x/80 - 5x/80
(75 - 60)/2 = (8x - 5x)/80
15/2 = 3x/80
80 * 15/2 = 3x
40 * 15 = 3x
600 = 3x
x = 600/3
x = 200 pounds
Answer:
I attached the answers :)
Step-by-step explanation:
hope this helps :)
(Its a bit messy becuz i used a mouse to write, sry about that)
Y = kx where k is a constant
27 = k*9
k = 27/9 = 3
required variation is y = 3x
Answer:
(a) 112, 28, 7, (7/4), (7/16)
Step-by-step explanation:
The sequence is given by the explicit formula
The terms of the sequence are :