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kondor19780726 [428]
3 years ago
9

Which information is not necessary to solve this problem?

Mathematics
1 answer:
saw5 [17]3 years ago
3 0
<span>1 Forty guests were invited to the party.
2 </span><span>her book has 200 pages
3</span><span> the number of people at Friday's, Saturday's, and Sunday's performances combined
4</span><span> number of friends at party
5 </span><span>the distance to the beach </span>
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Ben is taking guitar classes three times a week for 8eeeks each class will last 1 3/4 hours how many hours will Ben have spent i
Cerrena [4.2K]

Answer:

14

Step-by-step explanation:

to find the answer to this you would have to ethier convert 1 3/4 to 1.75 or multiply top heavy fractions

converted way

1.75x8= 14   - stays the same

nonconverted way

7/4 x 8/1 = 56/4 = 14

etheir way you get the same answer

8 0
3 years ago
The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
natulia [17]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
3 years ago
PLEASE HELP!!!!!! ILL GIVE BRAINLIEST *EXTRA 40 POINTS** !! DONT SKIP :((
elena-14-01-66 [18.8K]

Answer:

yes

Step-by-step explanation:

I think sorry if I am wrong

8 0
3 years ago
Read 2 more answers
Which of the following equations could be used to solve the given equation?
Pepsi [2]
If we simplify like terms on left and right sides we gwt

16x + 9 =  4x

Its B
8 0
3 years ago
Read 2 more answers
Given the regular octagon, what is the length of any side?
Jlenok [28]

Answer:110

Step-by-step explanation:x^2+17x=15x+35

x^2+17x-15x-35=0

x^2+2x-35=0

delta=2^2-4*1*(-35)=4+140=144

x1=(-2+V144)/2=(-2+12)/2=10/2

x=5

so 15*5+35=75+35=110

3 0
3 years ago
Read 2 more answers
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