Someone plss help ehgfsbehgbake

How can you subtract mixed numbers when the fractions in the first mixed number is less than the fraction in the second mixed nu

VARVARA [1.3K]

Answer:

To subtract mixed numbers, subtract the whole number parts of the mixed numbers and then subtract the fraction parts in the mixed numbers. Finally, combine the whole number answer and the fraction answer to express the answer as a mixed number. Subtract. Simplify the answer and write as a mixed number.

Step-by-step explanation:

5 0

4 years ago

A university claims that the average cost of books per student, per semester is $300. A group of students believes that the actu

LenKa [72]

Answer:

$t=\frac{345-300}{\frac{200}{\sqrt{100}}}=2.25$

$p_v =P(t_{(99)}>2.25)=0.0133$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean is higher than 300 at 1% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=345$ represent the sample mean

$s=200$ represent the sample standard deviation

$n=100$ sample size

$\mu_o =300$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 300, the system of hypothesis would be:

Null hypothesis: $\mu \leq 300$

Alternative hypothesis: $\mu > 300$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{345-300}{\frac{200}{\sqrt{100}}}=2.25$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=100-1=99$

Since is a one right tailed test the p value would be:

$p_v =P(t_{(99)}>2.25)=0.0133$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean is higher than 300 at 1% of significance.

7 0

4 years ago

Please help with this and pls explain how to got this in simple words! Thank you! Will give brainliest to the best answer! Pleas

KengaRu [80]

Answer:

$60775000

Step-by-step explanation:

Question ask for how much $ you lose in 52 weeks.

You're given that computer is down 2.75 hours per week. Each of those hours cost you $425000.

In other word, you loose 2.75×425000=$1168750 each week.

If 1 week cost you $1168750,

then 52 weeks, you'll lose 1168750×52=$60775000

8 0

3 years ago

How do you solve this math problem

marin [14]

D(t)=0.8 times 6 squared will equal to 28.8, when you do all of the math.

3 0

4 years ago

60% of the students in Mr. Vick's class have computers at home. If 21 students in his class have computers at home, how many stu

aleksley [76]

Answer:

There are 35 students in his class.

Step-by-step explanation:

1. Create a proportion: 60/100=21/x

2. Cross multiply, or not (I prefer to cross multiply). 60x=2100

3. Solve the equation: x=35.

Answer: There are 35 students in his class, 14 people going in school, 21 student online.

3 0

3 years ago