The answer is log3 k to the seventh power m to the sixth power over n to the ninth power
a * logₓ(y) = logₓ(yᵃ)
7 log₃ (k) = log₃ (k⁷)
6 log₃ (m) = log₃ (m⁶)
9 log₃ (n) = log₃ (n⁹)
7 log₃ (k) + 6 log₃ (m) - 9 log₃ (n) = log₃ (k⁷) + log₃ (m⁶) - log₃ (n⁹)
logₓ(y) + logₓ(z) = logₓ(y * z)
log₃ (k⁷) + log₃ (m⁶) - log₃ (n⁹) = log₃ (k⁷ * m⁶) - log₃ (n⁹)
logₓ(y) - logₓ(z) = logₓ(y / z)
log₃ (k⁷ * m⁶) - log₃ (n⁹) = log₃ (k⁷ * m⁶ / n⁹)
1.) 32
2.)42
3.)67
4.)78
5.) 13
6.)67
7.)23
8.80
Answer:
Sorry sorry sorry sorry!! Please forgive me! I need this to pass a very important exam!! Sorry again!! Ily!!
Step-by-step explanation:
Answer:
y= -3+x
Step-by-step explanation:
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ANSWER
The correct answer is

EXPLANATION
The expression given to us is,

We plug in

. That means we substitute 12 wherever we see x to obtain,

We simplify the parenthesis first to obtain,





Hence the expression evaluates to