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3 years ago

Please help me with thiss

Mathematics

1 answer:

Natasha_Volkova [10]3 years ago

5 0

Answer:

Step-by-step explanation:

8/12=6/9 TRUE

9/24=6/16 TRUE

12/15=15/20 FALSE (0.8 does not equal 0.75)

27/36=6/8 TRUE

Hope this helps!

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Please help me I can not figure it out

Anika [276]

Answer: 78

Step-by-step explanation: You do 3 * 26 to get your answer.

7 0

3 years ago

How do you solve 3 divided by x -1 = x + 1

Natasha2012 [34]

Answer:

multiply (x-1) to both sides and then subtract three from both sides

3 = (x-1)(x+1)

3 = (x^2 -1)

0 = x^2 - 4

(x-2)(x+2) = 0

x = 2

x = -2

Step-by-step explanation:

8 0

3 years ago

-24 divided by x + 12 to the second when x= -14

ELEN [110]

Answer:12

Step-by-step explanation:

3 0

3 years ago

In basketball, hang time is the time that both of your feet are off the ground during a jump. The equation for hang time is t =

const2013 [10]

Considering the hang time equation, it is found that Player 1 jumped 0.68 feet higher than Player 2.

<h3>What is the hang time equation?</h3>

The hang-time of the ball for a player of jump h is given by:

$t = 2\left(\frac{2h}{32}\right)^{\frac{1}{2}}$

The expression can be simplified as:

$t = 2\sqrt{\frac{h}{16}}$

For a player that has a hang time of 0.9s, the jump is found as follows:

$0.9 = 2\sqrt{\frac{h}{16}}$

$\sqrt{\frac{h}{16}} = \frac{0.9}{2}$

$(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.9}{2}\right)^2$

$h = 16\left(\frac{0.9}{2}\right)^2$

h = 3.24 feet.

For a player that has a hang time of 0.8s, the jump is found as follows:

$0.8 = 2\sqrt{\frac{h}{16}}$

$\sqrt{\frac{h}{16}} = \frac{0.8}{2}$

$(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.8}{2}\right)^2$

$h = 16\left(\frac{0.8}{2}\right)^2$

h = 2.56 feet.

The difference is given by:

3.24 - 2.56 = 0.68 feet.

More can be learned about equations at brainly.com/question/25537936

#SPJ1

3 0

2 years ago

If sinx+sin^2x=1 then what is the value of cos^12x+3cos^10x+3cos^8x+cos^6x

mr_godi [17]

$\sin x+\sin^2x=1\implies\sin x=1-\sin^2x=\cos^2x$

$\cos^{12}x+3\cos^{10}x+3\cos^8x+\cos^6x=\sin^6x+3\sin^5x+3\sin^4x+\sin^3x$
$=\sin^3x(\sin^3x+3\sin^2x+3\sin x+1)$
$=\sin^3x(\sin x+1)^3$

Let $y=\sin x$ . Then

$\sin^2x+\sin x-1=0\iff y^2+y-1=0\implies y=-\varphi,y=\varphi-1$

where $\varphi=\dfrac{1+\sqrt5}2\approx1.61803$ is the golden ratio.

$\begin{cases}y=-\varphi\\y=\varphi-1\end{cases}\implies\begin{cases}\sin x=-\varphi\\\sin x=\varphi-1\end{cases}$

Since $|\sin x|\le1$ for all real $x$ , we can omit the first equation, leaving us with

$\sin x=\varphi-1\approx0.61803$

$\cos^{12}x+3\cos^{10}x+3\cos^8x+\cos^6x=\sin^3x(\sin x+1)^3$
$=(\varphi-1)^3\varphi^3$
$=1$

where the last equality follows from the fact that $\varphi=1+\dfrac1\varphi$ .

7 0

3 years ago