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Murljashka [212]
3 years ago
12

Lukas is investing $16 000 that he would like to grow to at least $100 000 by the

Mathematics
1 answer:
N76 [4]3 years ago
4 0

Answer:

3.7

Step-by-step explanation:

Using GDC

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Can anyone help me choose the correct answer?!
lara [203]

Answer:

f(x)=x-6 is your answer.

when x=0

f(0)=0-6=-6

similarly other too

7 0
3 years ago
Jack is trying to determine how he can save money by cutting his electricity bill. He is currently on a standard use plan for el
faust18 [17]
Jack's current monthly bill is
  (1200 kWh +400 kWh)*($0.075/kWh) = $120

On the interval use plan, Jack's monthly bill would be
  (1200 kWh)*($0.03/kWh) + (400 kWh)*($0.15/kWh) = $36 + 60 = $96

If Jack were to switch, his savings would be $120 -96 = $24.

The appropriate choice is ...
  b. Jack should switch to the interval use plan, which would save him $24 per month.
7 0
3 years ago
Read 2 more answers
Multiply: (3x + 2)(4x - 7)
svetoff [14.1K]
When you are doing distribution with this problem you are going to get your answer of....
D) 12x^2 - 13x - 14

Steps:
Simplify...
<span>(3x + 2)(4x - 7)
= (3x + 2) (4x + -7)
= (3x)(4x) + (3x)(-7) + (2)(4x) + (2)(-7)

= 12x^2 - 21x + 8x - 14
=12x^2 - 13x -14</span>
5 0
4 years ago
Jasmine will buy the same number of stamps every month to add to a stamp collection her grandfather gave her. The table shows th
ololo11 [35]

Answer:

It is D

Step-by-step explanation:

It could be A but if we read the sentence correctly than we should understand about the number of stamps she bought in every month and how much her grandmother gave her.We should also read the options more than 10 times to understand it

7 0
3 years ago
A marketing research company desires to know the mean consumption of milk per week among males over age 32. A sample of 710 male
nydimaria [60]

Answer:

(4.5, 4.7)

Step-by-step explanation:

Hi!

Lets call X to the consumption of milk per week among males over age 32. X has a normal distribution with mean μ and standard deviation σ.

X \sim N(\mu, \sigma)

When you know the population standard deviation σ of X  ,  and the sample mean is \hat X, the  variable q has distribution N(0,1):

q = \frac{\hat X - \mu}{\sigma} \sim N(0,1)

Then you have:

P(-k < q

This defines a C - level confidence interval. For each C the value of k is well known. In this case C = 0.98, then k = 2.326

Then the confidence interval is:

(4.6 - 2.326*\frac{0.8}{\sqrt{710}}, 4.6 + 2.326*\frac{0.8}{\sqrt{710}})\\ (4.5, 4.7)

5 0
4 years ago
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