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Lynna [10]
3 years ago
13

Answer these with a explanation PLEASE.

Mathematics
1 answer:
Sedbober [7]3 years ago
6 0

Where are the questions?

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Please help me with these
Alex Ar [27]
When we approach limits, we are finding values that are infinitesimally approaching this x-value. Essentially, we consider the approximate location that this root or limit appears. This is essential when it comes to taking Calculus, and finding the limit or rate of change of a function.

When we are attempting limits questions, there are several tests we attempt first.

1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)
\lim_{x \to 0} (\frac{sinx}{x}) = 1
\lim_{x \to 0} (\frac{tanx}{x}) = 1
4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.

For example:

1) \lim_{x \to 0}\frac{\sqrt{x} - 5}{x - 25}

We can do this using the first and second method.
<em>Method 1: Direct evaluation:</em>

Substitute x = 0 to the function.
\frac{\sqrt{0} - 5}{0 - 25}
= \frac{-5}{-25}
= \frac{1}{5}

<em>Method 2: Rearranging the function
</em>

We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
By rewriting it in this form, the top will cancel with the bottom easily, and our limit comes out the same.

\lim_{x \to 0}\frac{(\sqrt{x} - 5)}{(\sqrt{x} - 5)(\sqrt{x} + 5)}
= \lim_{x \to 0}\frac{1}{(\sqrt{x} + 5)}}
= \frac{1}{5}

Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.
8 0
3 years ago
Find the sum of the first 10 terms of the following geometric sequences:<br> {3, 6, 12, 24, 48...)
bonufazy [111]

Answer:

3069

Step-by-step explanation:

q=6/3=2

s10=3(2^10-1)÷(2-1)=3×(1024-1)=

3069

because sn=a1(q^n-1)/(q-1)

3 0
4 years ago
Solve for x.3(3x - 1) + 2(3 - x) = 0
mote1985 [20]
9x-3+6-2x=0
7x+3=0
X=-3/7
5 0
4 years ago
Read 2 more answers
A class consisting of 4 graduate and 12 undergraduate students is random divided into 4 groups of 4. what is the probability tha
MrRissso [65]
Total = 16
Graduates = 4

\frac{4}{16}  =  \frac{1}{4}
\frac{1}{4}  \div 4  \\ =  \frac{1}{4}  \times  \frac{1}{4}  \\  =  \frac{1}{16}
\frac{1}{16}  = 0.0625
Rounding off to 2 decimal places,
Answer is 0.06

Hope this helps. - M
5 0
4 years ago
Help Please!!!!!!!!!!!<br><br> Questions 9 and 10
Sphinxa [80]

Answer:

Step-by-step explanation:

9

1. ∠ACB ≅∠ECD ; vertical angles are congruent (A)

2. C is midpoint of AE ; given

3. AC ≅CE; midpoint divides the line segment in 2 congruent segments (S)

4.AB║DE; given

5. ∠A≅∠E; alternate interior angles are congruent (A)

6. ΔABC≅ΔEDC; Angle-Side-Angle congruency theorem

10

1. YX≅ZX; given (S)

2. WX bisects ∠YXZ; given

3. ∠YXW≅∠ZXW; definition of angle bisectors (A)

4. WX ≅WX; reflexive propriety(S)

5. ΔWYX≅ΔWZX; Side-Angle-Side theorem

3 0
3 years ago
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