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Svetradugi [14.3K]
3 years ago
14

Which zero pair could be added to the function f(x)=x2+12x+6 so that the function can be written in vertex form?

Mathematics
1 answer:
alex41 [277]3 years ago
8 0
Find the vertex.

x=b/-2a

12/-2(1)
x=-6

then plug into equation

-6^2+12(-6)+6

36-72+6=-30

(-6,-30)
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A. 36<br> B. 12<br> C. 80<br> D. 60<br> E. 48<br> F. 20
Art [367]

Answer:

it's d because it's correct

Step-by-step explanation:

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=-5x-16%2B9x%2Bx-1" id="TexFormula1" title="-5x-16+9x+x-1" alt="-5x-16+9x+x-1" align="absmiddle
Talja [164]

Answer:

I have no clue what it is sorry

7 0
3 years ago
the point 3,2 lies on a circle.what is the exact length of the radius of this circle if the center is located at (-1,-4)
Crazy boy [7]
You can use the distance formula to solve this.

Distance Formula:
d = \sqrt{(X_2 -X_1)^2 + (Y_2 - Y_1)^2}

I am going to use point (3,2) as point 1 and (-1,-4) as point 2
Insert the points into the formula
d = \sqrt{(X_2 -X_1)^2 + (Y_2 - Y_1)^2}
d = \sqrt{((-1) - 3)^2 + ((-4) - 2)^2}
Solve:
d = \sqrt{((-1) - 3)^2 + ((-4) - 2)^2}
d = \sqrt{(-4)^2 + (-6)^2}
d = \sqrt{16 + 36}
d = \sqrt{52}
d = \sqrt{52} = \sqrt{4}\sqrt{13}
d = \sqrt{52} = 2 \sqrt{13}
d = 2 \sqrt{13}
radius = 2 \sqrt{13} = 7.2111


5 0
3 years ago
Function is defined by f(x) = x2 - 4x + 8. The graph of function g is shown.
xenn [34]

Answer:5

Step-by-step explanation:

couldn’t tell ya g

3 0
3 years ago
Devin has a furniture store. He sold a shoe rack recently for 3450. It cost him just 2300 to make the rack
True [87]

Answer:

50%

Step-by-step explanation:

3450 - 2300 = 1150

1150/ 2300 × 100 = 50

5 0
3 years ago
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