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Marta_Voda [28]
3 years ago
5

PLEASE HELP!!!!

Mathematics
1 answer:
bearhunter [10]3 years ago
3 0

Answer:

19/5= 3 4/5.

Step-by-step explanation:

19 divided by 5 equals 3 with a left over of 4. So 3 and 4/5 should be the answer. hope this helps! have a good day!

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Solve y (1/2)y+6=(3/4)y–4
iren [92.7K]

Answer:

Y = 40

Step-by-step explanation:

Change 1/2 to 2/4

2/4 y + 6 = 3/4y - 4

subtract 2/4y

6 = 1/4y -4

add 4

10 = 1/4y

multiply by 4 to get fraction to 1y or y

y = 40

8 0
3 years ago
Read 2 more answers
A home builder obtained a preconstruction loan of $50,000 for 8 months at an annual interest rate of 9.5%. What is the simple in
kykrilka [37]
Annual interest
50000 * (9.5 / 100)
4750

Interest for 12 months = 4750
Interest for 8 months 
(4750/12) * 8
$ 3166.67
8 0
4 years ago
A factory has three machines making energy drinks. When all three machines are running, 520 drinks are made each hour. When only
Vinil7 [7]

Let A, B and C be the amount machines A, B and C, respectively, produce each hour alone.

With all three machines together produce 520 drinks each hour, we know that the addition of the amount that each produces each hour is equal to 520, that is.

A+B+C=520_{}

Now, similarly, machines A and B produce together 320 drinks each hour, so the sum of the amounts A and B produce each hour is equal to 320, so:

A+B=320

If machine C produce 30 more drinks than B each hour, than the amount of B plus 30 will be the amount of C:

C=B+30

So, we got the system of equations:

\begin{gathered} A+B+C=520 \\ A+B=320 \\ C=B+30 \end{gathered}

To solve, notice that A + B is known, because of the second equation, so we can substitute A + B by 320 in the first equation:

\begin{gathered} (A+B)+C=520 \\ 320+C=520 \\ C=520-320=200 \end{gathered}

Now, we can substitute C into the third equation and solve for B:

\begin{gathered} C=B+30 \\ 200=B+30 \\ B+30=200 \\ B=200-30=170 \end{gathered}

And, finally, we can substitute B into the second equation and solve for A:

\begin{gathered} A+B=320 \\ A+170=320 \\ A=320-170=150 \end{gathered}

Answers:

First box:

A+B+C=520

Second box:

A+B=320

Third box:

C=B+30

Fourth box:

150

3 0
1 year ago
A local hamburger shop sold a combined total of 559 hamburgers and cheeseburgers on Saturday. There were 59 more cheeseburgers s
tangare [24]
Let H be hamburger and C be chesseburger.

H+C=559
H+59=C

H+(H+59)=559
2H+59+559

2H=559-59
2H=500

H=500/2
H=250

250 hamburgers were sold on Saturday.
5 0
4 years ago
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Evaluate the expression.<br> 23 [+ 4(36 =<br> 12)]
andreyandreev [35.5K]

Step-by-step explanation:

23(+4(36=12))

23(144=48

3312=1104

4 0
3 years ago
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