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Trava [24]
3 years ago
12

A home builder obtained a preconstruction loan of $50,000 for 8 months at an annual interest rate of 9.5%. What is the simple in

terest due on the loan?
Mathematics
1 answer:
kykrilka [37]3 years ago
8 0
Annual interest
50000 * (9.5 / 100)
4750

Interest for 12 months = 4750
Interest for 8 months 
(4750/12) * 8
$ 3166.67
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Math help ohh yup #5 in the middle
UkoKoshka [18]

Answer:

m<7 = 49°

m<8 = 41°

m<9 = 49°

m<10 = 41°

Step-by-step explanation:

Given :

m<7 ≅ m<9

m<8 = 41°

m<7 = 90° - m<8 (complementary angles)

m<7 = 90° - 41° (substitution)

m<7 = 49°

m<9 = m<7 (m<7 ≅ m<9)

m<9 = 49° (substitution)

m<10 = 90 - m<9

m<10 = 90 - 49

m<10 = 41°

8 0
3 years ago
Divide 300 in a ratio of 3/7
Talja [164]

in short, we simply divide the whole 300 by (3+7), to get in a 3:7 ratio, and then distribute accordingly.


\bf 300\qquad 3:7\qquad \cfrac{3}{7}~\hspace{5em}\cfrac{3\cdot \frac{300}{3+7}}{7\cdot \frac{300}{3+7}}\implies \cfrac{3\cdot 30}{7\cdot 30}\implies \cfrac{90}{210}\implies 90:210

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Given: f(x)=1-x^2,g(x)=1-2x, and h(x)= 1/x^2+1 <br> find g(f(5))
Novay_Z [31]

Answer:

g(x) = -9

Step-by-step explanation:

g(x) = 1 - 2x        substitute 5 for x

g(x) = 1 - 2(5)      solve parenthesis first

g(x) = 1 - 10         subtract

g(x) = -9

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If Triangle J K L is congruent to Triangle B C A, which statement must be true?
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Step-by-step explanation:

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A forestry company hopes to generate credits from the carbon sequestered in its plantations.The equation describing the forest w
Dmitry [639]

Answer:

Explanation:

Given:

The equation describing the forest wood biomass per hectare as a function of plantation age t is:

y(t) = 5 + 0.005t^2 + 0.024t^3 − 0.0045t^4

The equation that describes the annual growth in wood biomass is:

y ′ (t) = 0.01t + 0.072t^2 - 0.018t^3

To find:

a) The year the annual growth achieved its highest possible value

b) when does y ′ (t) achieve its highest value?

a)

To determine the year the highest possible value was achieved, we will set the derivative y'(t) to zero. The values of t will be substituted into the second derivative to get the highest value

\begin{gathered} 0\text{ = 0.01t + 0.072t}^2\text{ - 0.018t}^3 \\ using\text{ a graphing tool,} \\ t\text{  = -0.1343} \\ \text{t = 0} \\ t\text{ = 4.1343} \\  \\ Since\text{ we can't have time as a negative value, t = 0 or t = 4.1343} \end{gathered}\begin{gathered} To\text{ ascertain which is the maximum, we take a second derivative} \\ y^{\prime}\text{'\lparen t\rparen = 0.01 + 0.144t - 0.054t}^2 \\  \\ substitute\text{ t = 0 and t = 4.13 respectively} \\ when\text{ t = 0 } \\ y^{\prime}\text{'\lparen t\rparen= 0.01 + 0.144\lparen0\rparen - 0.054\lparen0\rparen}^2 \\ y^{\prime}\text{'\lparen t\rparen= 0.01 + 0 - 0} \\ y^{\prime}\text{'\lparen t\rparen= 0.01 > 0} \\  \\ y^{\prime}\text{'\lparen t\rparen= 0.01 + 0.144\lparen4.13\rparen - 0.054\lparen4.13\rparen}^2 \\ y^{\prime}\text{'\lparen t\rparen= -0.316 < 0} \\  \\ if\text{ }y^{\prime}\text{'\lparen t\rparen > 0 , then it is minimum, } \\ if\text{ }y^{\prime}\text{'\lparen t\rparen < 0, then it is maximum} \end{gathered}

SInce t = 4.13, gives y ′' (t) = -0.316 (< 0). This makes it the maximum value of t

The year the annual growth achieved its highest possible value to the nearest whole number will be

year 4

b) y ′ (t) will achieve its highest value, when we substitute the value of t that gives into the initial function.

Initial function: y(t) = 5 + 0.005t^2 + 0.024t^3 − 0.0045t^4

undefined

6 0
1 year ago
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