Answer:
m<7 = 49°
m<8 = 41°
m<9 = 49°
m<10 = 41°
Step-by-step explanation:
Given :
m<7 ≅ m<9
m<8 = 41°
m<7 = 90° - m<8 (complementary angles)
m<7 = 90° - 41° (substitution)
m<7 = 49°
m<9 = m<7 (m<7 ≅ m<9)
m<9 = 49° (substitution)
m<10 = 90 - m<9
m<10 = 90 - 49
m<10 = 41°
in short, we simply divide the whole 300 by (3+7), to get in a 3:7 ratio, and then distribute accordingly.

Answer:
g(x) = -9
Step-by-step explanation:
g(x) = 1 - 2x substitute 5 for x
g(x) = 1 - 2(5) solve parenthesis first
g(x) = 1 - 10 subtract
g(x) = -9
Answer:
JKL=BCA
Step-by-step explanation:
Answer:
Explanation:
Given:
The equation describing the forest wood biomass per hectare as a function of plantation age t is:
y(t) = 5 + 0.005t^2 + 0.024t^3 − 0.0045t^4
The equation that describes the annual growth in wood biomass is:
y ′ (t) = 0.01t + 0.072t^2 - 0.018t^3
To find:
a) The year the annual growth achieved its highest possible value
b) when does y ′ (t) achieve its highest value?
a)
To determine the year the highest possible value was achieved, we will set the derivative y'(t) to zero. The values of t will be substituted into the second derivative to get the highest value


SInce t = 4.13, gives y ′' (t) = -0.316 (< 0). This makes it the maximum value of t
The year the annual growth achieved its highest possible value to the nearest whole number will be
year 4
b) y ′ (t) will achieve its highest value, when we substitute the value of t that gives into the initial function.
Initial function: y(t) = 5 + 0.005t^2 + 0.024t^3 − 0.0045t^4