Answer:
Jogging 6th time.
Step-by-step explanation:
We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.
We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.
We know that an arithmetic sequence is in form 
, where,
= nth term of sequence,
= 1st term of sequence,
n = Number of terms in sequence,
d = Common difference.
Let us find common difference of our given sequence as:
Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.
Let us solve for n.
We can also write next terms of our sequence as:
Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.
The answer is -12x^4y^4 !
Answer:
72
Step-by-step explanation:
plz mark brainliest :D
My answer isn't in your choices so it's probably wrong, but hopefully my approach can give you hints.
The vowels are AEAI
The vowels can be arranged in 4*3*2=24 ways.
The non vowels are MTHMTCS
If the vowels must be together, there have to be in one of the spaces between the non vowels.
If we look at it like this:
-M-T-H-M-T-C-S-
The 4 vowels must go in one of the places marked with a dash.
There are thus 8 places to choose from.
But we must also consider that the non vowels can be arranged in any way. There are 7 of them, so they can be arranged in 7*6*5*4*3*2=5040 ways.
Multiply everything together to get 8*5040*24=967680
