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Alexus [3.1K]
2 years ago
6

A ​$300 suit is marked down by ​%20. Find the sale price

Mathematics
2 answers:
avanturin [10]2 years ago
7 0

Answer:

1499

5

(Decimal: 299.8)

Step-by-step explanation: =

300

1

−

20

100

=

300

1

+

−20

100

=

300

1

+

−1

5

=

1500

5

+

−1

5

=

1500+−1

5

il63 [147K]2 years ago
6 0

Percentage off= 20% of $300
X=0.2(300)
X=60

NOT DONE YET!!
Still need to find the sale price

Sale price=original price - percentage off
X=300-60
X=240

Answer: $240 is the sale price.

If this helps, mark me brainliest please! :)
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A right circular cylindrical metallic rod is 15 inches tall. The radius of the base is 2 inches. What is the surface area of the
Artyom0805 [142]

Answer: Surface area = 68π inches²

Step-by-step explanation:

The formula for determining the total surface area of the circular cylindrical metallic rod is expressed as

Total surface area = 2πr² + 2πrh

Where

r represents the radius of the cylindrical rod.

h represents the height of the cylindrical rod.

π is a constant whose value is 3.14

From the information given,

Radius = 2 inches

Height = 15 inches

Therefore,

Surface area = (2 × π × 2²) + 2 × π × 2 × 15) = 8π + 60π

Surface area = 68π inches²

4 0
2 years ago
Let D be a region bounded by a simple closed path C in the xy-plane. The coordinates of the centroid ( , ) of D are given below,
san4es73 [151]

Answer:

the answer is- 0.09

Step-by-step explanation:

You sound smart!

3 0
2 years ago
Grade 10 math anyone?
Kisachek [45]

Answer:

6 years

Step-by-step explanation:

Here,

I=60

P=200

R=0.05

and we need to find T.

So using the formula I=PRT, we can find T by substituting the values

60 = (200)(0.05)T

60=10T

T=\frac{60}{10} = 6 years

8 0
2 years ago
Which function is the same as y = 3 cosine (2 (x startfraction pi over 2 endfraction)) minus 2? y = 3 sine (2 (x startfraction p
kirza4 [7]

The function which is same as the function y = 3cos(2(x +π/2)) -2 is: Option A: y= 3sin(2(x + π/4)) - 2

<h3>How to convert sine of an angle to some angle of cosine?</h3>

We can use the fact that:

\sin(\theta) = \cos(\pi/2 - \theta)\\\sin(\theta + \pi/2) = -\cos(\theta)\\\cos(\theta + \pi/2) = \sin(\theta)

to convert the sine to cosine.

<h3>Which trigonometric functions are positive in which quadrant?</h3>
  • In first quadrant (0 < θ < π/2), all six trigonometric functions are positive.
  • In second quadrant(π/2 < θ < π), only sin and cosec are positive.
  • In the third quadrant (π < θ < 3π/2), only tangent and cotangent are positive.
  • In fourth (3π/2 < θ < 2π = 0), only cos and sec are positive.

(this all positive negative refers to the fact that if you use given angle as input to these functions, then what sign will these functions will evaluate based on in which quadrant does the given angle lies.)

Here, the given function is:

y= 3\cos(2(x + \pi/2)) - 2

The options are:

  1. y= 3\sin(2(x + \pi/4)) - 2
  2. y= -3\sin(2(x + \pi/4)) - 2
  3. y= 3\cos(2(x + \pi/4)) - 2
  4. y= -3\cos(2(x + \pi/2)) - 2

Checking all the options one by one:

  • Option 1: y= 3\sin(2(x + \pi/4)) - 2

y= 3\sin(2(x + \pi/4)) - 2\\y= 3\sin (2x + \pi/2) -2\\y = -3\cos(2x) -2\\y = 3\cos(2x + \pi) -2\\y = 3\cos(2(x+ \pi/2)) -2

(the last second step was the use of the fact that cos flips its sign after pi radian increment in its input)
Thus, this option is same as the given function.

  • Option 2: y= -3\sin(2(x + \pi/4)) - 2

This option if would be true, then from option 1 and this option, we'd get:
-3\sin(2(x + \pi/4)) - 2= -3\sin(2(x + \pi/4)) - 2\\2(3\sin(2(x + \pi/4))) = 0\\\sin(2(x + \pi/4) = 0

which isn't true for all values of x.

Thus, this option is not same as the given function.

  • Option 3: y= 3\cos(2(x + \pi/4)) - 2

The given function is y= 3\cos(2(x + \pi/2)) - 2 = 3\cos(2x + \pi) -2 = -3\cos(2x) -2

This option's function simplifies as:

y= 3\cos(2(x + \pi/4)) - 2 = 3\cos(2x + \pi/2) -2 = -3\sin(2x) - 2

Thus, this option isn't true since \sin(2x) \neq \cos(2x) always (they are equal for some values of x but not for all).

  • Option 4: y= -3\cos(2(x + \pi/2)) - 2

The given function simplifies to:y= 3\cos(2(x + \pi/2)) - 2 = 3\cos(2x + \pi) -2 = -3\cos(2x) -2

The given option simplifies to:

y= -3\cos(2(x + \pi/2)) - 2 = -3\cos(2x + \pi ) -2\\y = 3\cos(2x) -2

Thus, this function is not same as the given function.

Thus, the function which is same as the function y = 3cos(2(x +π/2)) -2 is: Option A: y= 3sin(2(x + π/4)) - 2

Learn more about sine to cosine conversion here:

brainly.com/question/1421592

4 0
2 years ago
Read 2 more answers
A clinical trial was conducted to test the effectiveness of the drug zopiclone for treating insomnia in older subjects. Before t
aleksklad [387]

Answer:

We cannot say that the mean wake time are different before and after the treatment, with 98% certainty. So the zopiclone doesn't appear to be effective.

Step-by-step explanation:

The goal of this analysis is to determine if the mean wake time before the treatment is statistically significant. The question informed us the mean wake time before and after the treatment, the number of subjects and the standard deviation of the sample after treatment. So using the formula, we can calculate the confidence interval as following:

IC[\mu ; 98\%] = \overline{y} \pm t_{0.99,n-1}\sqrt{\frac{Var(y)}{n}}

Knowing that t_{0.99,15} = 2.602:

IC[\mu ; 98\%] = 98.9 \pm 2.602\frac{42.3}{4} \Rightarrow 98.9 \pm 27.516

IC[\mu ; 98\%] = [71.387 ; 126,416]

Note that 102.8 \in [71.384 ; 126.416] so we cannot say, with 98% confidence, that the mean wake time before treatment is different than the mean wake time after treatment. So the zopiclone doesn't appear to be effective.

7 0
3 years ago
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