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jolli1 [7]
3 years ago
11

What are the degree and zeros of the polynomial f(x) = (x-2)^5?

Mathematics
1 answer:
Vitek1552 [10]3 years ago
8 0

Answer: D

Step-by-step explanation:

just took the edge test

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Step-by-step explanation:

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Hence, (x - 5) ≥ 0

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Now, for all x values that are greater than equal to 5 the value of - \sqrt{x - 5} will be negative.

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⇒ - \sqrt{x - 5} + 3 \leq  3

⇒ y ≤ 3

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