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3 years ago

PLEASE ANSWER FAST

Mathematics

2 answers:

Brrunno [24]3 years ago

7 0

Answer:

Step-by-step explanation:

A. 2.25 and 0.5

B. 1 tomato

neonofarm [45]3 years ago

6 0

Answer:

A. 2.25 and 0.5

B. 1 tomato

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I'm retaking what do you think it is

puteri [66]

Answer:

Step-by-step explanation:

Its very simple try not to waste your points

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3 years ago

Question choices: A: I, IV B: II, III, IV C: III, IV D: II, III

gulaghasi [49]

0Answer:

Step-by-step explanation:

Find the zeros by letting y = 0 , that is

x² - x - 6 = 0 ← in standard form

(x - 3)(x + 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 3 = 0 ⇒ x = 3

x + 2 = 0 ⇒ x = - 2

Since the coefficient of the x² term (a) > 0

Then the graph opens upwards and will be positive to the left of x = - 2 and to the right of x = 3 , that is in the intervals

(-∞, - 2) and (3, ∞ ) → option A

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3 years ago

Find the sum. 5k/k^2-2k+1 + 2/k^2+k-2

Alchen [17]

$\dfrac{5k}{\underbrace{k^2-2k+1}_{(a-b)^2=a^2-2ab+b^2}}+\dfrac{2}{k^2+k-2}=\dfrac{5k}{(k-1)^2}+\dfrac{2}{k^2+2k-k-2}\\\\=\dfrac{5k}{(k-1)^2}+\dfrac{2}{k(k+2)-1(k+2)}=\dfrac{5k}{(k-1)^2}+\dfrac{2}{(k+2)(k-1)}\\\\=\dfrac{5k(k+2)}{(k-1)^2(k+2)}+\dfrac{2(k-1)}{(k-1)^2(k+2)}=\dfrac{5k^2+10k+2k-2}{(k-1)^2(k+2)}$
$=\dfrac{5k^2+12k-2}{(k-1)^2(k+2)}=\dfrac{5k^2+12k-2}{(k^2-2k+1)(k+2)}\\\\=\dfrac{5k^2+12k-2}{k^3+2k^2-2k^2-4k+k+2}=\dfrac{5k^2+12k-2}{k^3-3k+2}$

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3 years ago

3z2−6z for z=5 Please help?!!

ludmilkaskok [199]

Answer:

3z+2= x ; z=5

3(5)+2

15+2

Step-by-step explanation:

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3 years ago

What fraction has the greatest value 5/6, 7/12, 7/10

White raven [17]

First you have to make them to a common denominator.
5/6 7/12 7/10
50/60 35/60 42/60
from these the greatest value is 35/60 because 35 parts of 60 is bigger than the rest.
so the answer is 7/12

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3 years ago