2 years ago

Someone please help!

Mathematics

1 answer:

valentina_108 [34]2 years ago

8 0

Answer:

x = 33

Step-by-step explanation:

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Let as consider the complete ques is : Ray QS bisects ∠PQR. Solve for x and find m∠PQR. m∠PQS = 3x ; m∠SQR = 5x-20.

Given:

Ray QS bisects ∠PQR.

m∠PQS = 3x

m∠SQR = 5x-20

To find:

The value of x and m∠PQR

Solution:

Ray QS bisects ∠PQR. So,

$m\angle PQS=m\angle SQR$

$3x=5x-20$

$3x-5x=-20$

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The value of x is 10.

Now,

$m\angle PQR=m\angle PQS+m\angle SQR$

$m\angle PQR=3x+5x-20$

$m\angle PQR=8x-20$

Put x=10,

$m\angle PQR=8(10)-20$

$m\angle PQR=80-20$

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Therefore, the m∠PQR is 60 degrees.

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