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Mrac [35]
2 years ago
7

July average temperature: 78°F,January average temperature: 52°F What is the percentage difference?

Mathematics
1 answer:
ycow [4]2 years ago
6 0
I’m guessing you subtract 78-52 then divide by original which was 52.. so July is 50% warmer.
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Question: Consider the domain (D) and rule of each function. Determine the range of the function. 1. D = {0, 1, 2, 3}; f(x) = 3x
Maksim231197 [3]

For every function you need evaluate the function for every value in the domain D. And the collection of this values correspond to the range of the function.

1. D = \{0,1,2,3 \}, R = \{f(0), f(1), f(2), f(3) \} = \{-5, -2, 1, 4 \}.

2. D = \{-1,0,1 \}; R= \{f(-1), f(0), f(1)\} = \{0, 1, 0 \} = \{0,1\}

3. D = \{-2,-1,0,1 \}; R = \{f(-2), f(-1), f(0), f(1) \} = \{0, -2, -2, 0 \} = \{-2,0\}

4. D = \{0,1,2,3 \}; R =\{f(0), f(1), f(2), f(3) \} = \{3, 1, -1, -3 \}

5 0
3 years ago
Need help with geometry question?
Nuetrik [128]

Answer: A, Corresponding; Vertical


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5 0
3 years ago
The graph shows the high temperatures on july 4th over a 15 year period plz look at graph will give brainliest
jeka57 [31]
Well there are 8 years that show over 90°. Using those statistics you can show that as 8/15 for a probability.
7 0
3 years ago
Read 2 more answers
When expressed in scientific notion the number 1,230,000,000 is 1.23 x 10B. The value of B is.
gladu [14]
I hope this helps you



123×1000000000


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6 0
3 years ago
Kyle works at a donut​ factory, where a​ 10-oz cup of coffee costs 95cents​, a​ 14-oz cup costs​ $1.15, and a​ 20-oz cup costs​
choli [55]
Let x = no. of 10 oz cups sold
Let y = no. of 14 oz cups sold
Let z = no. of 20 oz cups sold
:
Equation 1: total number of cups sold:
x + y + z = 24
:
Equation 2: amt of coffee consumed:
10x + 14y + 20z = 384
:
Equation 3: total revenue from cups sold
.95x + 1.15y + 1.50z = 30.60
:
Mult the 1st equation by 20 and subtract the 2nd equation from it:
20x + 20y + 20z = 480
10x + 14y + 20z = 384
------------------------ subtracting eliminates z
10x + 6y = 96; (eq 4)

Mult the 1st equation by 1.5 and subtract the 3rd equation from it:
1.5x + 1.5y + 1.5z = 36.00
.95x + 1.15y+ 1.5z = 30.60
---------------------------subtracting eliminates z again
.55x + .35y = 5.40; (eq 5)

Multiply eq 4 by .055 and subtract from eq 5:
.55x + .35y = 5.40
.55x + .33y = 5.28
--------------------eliminates x
0x + .02y = .12
y = .12/.02
y = 6 ea 14 oz cups sold 

Substitute 6 for y for in eq 4
10x + 6(6) = 96
10x = 96 - 36
x = 60/10
x = 6 ea 10 oz cups

That would leave 12 ea 20 oz cups (24 - 6 - 6 = 12)

Check our solutions in eq 2:
10(6) + 14(6) + 20(12) =
60 + 84 + 240 = 384 oz

A lot steps, hope it made some sense! I hope this helps!! ;D

3 0
3 years ago
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