Speed=distance/time
average speed=(total distance)/(total time)
total distance=203+243=446
total time=3.5+4.5=8
average speed=(446)/(8)=55.75
answer is A
Area of pool edge = Area of big rectangle - Area of the pool
Area of pool edge = Area of the pool = 40 × 60 = 2400 ft²
2400 = Area of big rectangle - 2400
Area of big rectangle = 2400 + 2400
Area of big rectangle = 4800
Length × width = 4800
From the diagram, we need the length to be [x + x] more than the length of the pool, where x is the distance from the pool edge to the patio edge.
We also need the width of the big rectangle to be [[x + x] more than the width of the pool.
Length = 60 + 2x
Width = 40 + 2x
Length × Width = [60+2x] × [40+2x]
4800 = 2400 + 120x + 80x + 4x²
0 = 4x² + 200x - 2400
0 = 4[x² + 50x - 600]
0 = x² + 50x - 600
0 = [x - 60] [x + 10]
x - 60 = 0 OR x + 10 = 0
x = 60 OR x = -10
We can only use the positive value of x since the context is length
Hence, x = 60
Answer:
w = 2, EF = 30 , FG = 42
Explanation:
We have EF = 5w + 20 and FG = 7w + 28
Since these points E, F and G are col-linear points we have.
EG = EF + FG
And given that EG = 72
So, EF+EG = 72
5w + 20 + 7w + 28 = 72
12w + 48 = 72
12 w = 24
w = 2
So EF = 5w + 20 = 5x2 + 20 = 30
FG = 7w + 28 = 7x2 + 28 = 42
The letter C stands for the Circumference of the circle