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3 years ago

8

kevin is trying to find the height of a tree. he stands 100ft away from the tree and records the angle of elevation to the top o

f the tree to be 26. Kevins height is 6ft. how tall is the tree?

1 answer:

Morgarella [4.7K]3 years ago

6 0

Answer:

HERES YOUR ASSIGNMENT! I EDITED IT ON MICROSOFT SO THAT I CAN SCREENSHOT IT AND SEND IT TO YOU...I HOPE IT HELPS :)

<h3>ARIGATO OZAIMASU!!!</h3>

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In the united states , 13 out of every 20 cans are recycled what percent of cans are recycled

WARRIOR [948]

Answer:

75%

Step-by-step explanation:

3 0

3 years ago

Which terms in the following expression are like terms?

Alinara [238K]

9514 1404 393

Answer:

(c) 5x and 3x, and 4 and 1

Step-by-step explanation:

Like terms have the same variable(s) to the same power(s).

The terms of this expression are ...

x^3: variable x, power 3
5x: variable x, power 1
-3x: variable x, power 1
3y: variable y, power 1
4: no variable
-1: no variable

The like terms are {5x, -3x}, which have the x-variable to the first power, and {4, -1}, which have no variable.

6 0

3 years ago

Find the percent of decrease from 310 to 140. Round to the nearest tenth of a percent if necessary.

JulijaS [17]

54.8% I think I'm not sure

4 0

3 years ago

A nursery sells plants in flats. There are 6 plants in each tray. Each flat has six trays. The nursery sold 18 flats on Saturday

marshall27 [118]

For this case we have to:

There are 6 plants per tray.

There are 6 trays for each flat, so for each flat there are $6 * 6 = 36$ plants.

Saturday day: $18 flat * 36 plants = 648$

Thus, on Saturday they sold 648 plants.

Sunday: $21 flat * 36plants = 756$

Thus, on Saturday they sold 756 plants.

Thus, in total $648 +756 = 1404$ plants were sold.

Answer:

$648 +756 = 1404$ plants were sold.

3 0

3 years ago

Haya la integral de xarcsenx/((1-x^2)^1/2). Utiliza la sustitución de t= arcsenx

ikadub [295]

Answer:

<em>Explicación más abajo</em>

Step-by-step explanation:

Integración Indefinida

La integral

$I=\int \dfrac{x .arcsen\left(x\right)}{\sqrt{1-x^2}}$

Se resuelve con el cambio de variables:

t=arcsen(x)

Una vez hechos los cambios, la integral se resuelve en función de t:

$I=sen(t)-t.cos(t)+C$

Hay que devolver los cambios para mostrarla en función de x.

El cambio de variables también se puede escribir:

x=sen(t)

Recordando que

$cos(t)=\sqrt{1-sen^2(t)}$

Entonces:

$cos(t)=\sqrt{1-x^2}$

Devolviendo los cambios:

$I=sen(t)-t.cos(t)+C=x-arcsen(x)\sqrt{1-x^2}+C$

Es la respuesta correcta

7 0

3 years ago