Answer:
see attached
Step-by-step explanation:
No doubt you have examples showing the wording that is expected to be used here. We have made a guess.
power of a ratio: the numerator is raised to the power, as is the denominator. (a/b)^c = (a^c)/(b^c)
power of a product: each factor is raised to the power. (ab)^c = (a^c)(b^c)
power of a power: the powers are multiplied. (a^b)^c = a^(bc)
quotient of powers: the result when one power is divided by another is the difference of the numerator and denominator powers. (a^b)/(a^c) = a^(b-c)
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<em>Additional comment</em>
The order of operations tells you to simplify inside parentheses first. Doing that reduces the work somewhat.

x+y=120_______1
x=4*y_________2
x=4y
substitute 4y for x in equation 1
`4y+y=120
5y=120
eliminate the coefficient of y
y=120/5
y=24
now,input 24 for y in equation 2
`x=4y
x=4*24
x=96
thus, the numbers are
96 and 24
Answer:
Look at the unfolded cylinder down: it's consisted of a rectangle and 2 circles. so to find the surface area of the cylinder we should find the areas of the rectangle and the 2 circles.
1) A of 2 circles = 2(π
) = 2π
2) A of rectangle = base x height (or length x width) = bh
but the if we fold the rectangle? what will happen?
the base will go around the circle, this means that the base is equal to the circle circumference, which is 2πr.
Therefore, A of rectangle = 2πrh
3) Surface area of cylinder = 2π
+ 2πrh
simplify more and take the common factor 2πr:
= 2πr (r+h)
Answer:
B.
Step-by-step explanation:
x represents the amount of guests going to the birthday party, with the amount of money per guest being 12. You would multiply those two together, but as we do not know the total amount of guests, we keep it as a variable. 125 is the amount before the guests even know about the party, so therefore, you would need to use that equation.
Hi there!
The answer to this question is A - multiply by 1/2. This is because multiplying by 1/2 does not get rid of the 1/2 on that side, which is what we want to do.
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!