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Andrej [43]
3 years ago
10

Please answer this question :)

Mathematics
1 answer:
tatuchka [14]3 years ago
5 0

Answer:

2/5

Step-by-step explanation:

2/5

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An expression involves subtracting two numbers from a positive number. Under what circumstances with the value expression be neg
Svetach [21]
So (positive integer)-x-y can be negative
so to get a negative number as your result/answer, x+y must be greater than (positve integer) so  for example


lets say (positive integer)=8
x+y must be greater than 8 to make the equation negative so
example
x=5
y=4
x+y=9
8-9=-1
7 0
3 years ago
(x^2y^3) = (xy^a)^b
Rainbow [258]

Answer:

C. \frac{3}{2}

Step-by-step explanation:

To find the value f b, we need to compare the exponents.

The given exponential equation is:

( {x}^{2}  {y}^{3} )^{3}  = ( {x}  {y}^{a} )^{b}

Recall and apply the following rule of exponents.

( {x}^{m}  )^{n}  = {x}^{mn}

We apply this rule on both sides to get:

{x}^{2 \times 3}  {y}^{3 \times 3} =   {x}^{b}  {y}^{ab}

Simplify the exponents on the left.

{x}^{6}  {y}^{9} =   {x}^{b}  {y}^{ab}

Comparing exponents of the same variables on both sides,

b = 6 \: and \:\: ab = 9

\implies \: 6b = 9

Divide both sides by 6.

b =  \frac{9}{6}

b =  \frac{3}{2}

4 0
3 years ago
The accompanying stem-and-leaf plot represents Kiko's test scores this year. What is the median score for this set of data?
worty [1.4K]

Answer: 80

Write down all the values and cross out until you get to the middle, since there are 2 values, find the mean, which would be 80

6 0
3 years ago
1. How much heat is absorbed by a 50g iron skillet when its temperature rises from 10oC to 124oC? Joules
hoa [83]
<span>1. How much heat is absorbed by a 50g iron skillet when its temperature rises from 10oC to 124oC? Joules

Formula: Heat = mass * specific heat * ΔT

Data:
mass = 50 g = 0.050 kg
specific heat of iron = 450 J/ kg °C
ΔT = 124°C - 10°C ¿ 114 °C

=> heat = 0.050kg * 450 J / kg°C * 114°C ≈ 2.6 J

2. If a refrigerator is a heat pump that follows the first law of thermodynamics, how much heat was removed from food inside of the refrigerator if it released 492J of energy to the room? Joules

The firs law of thermodynamics is conservation of energy => energy removed from inside of the refrigerator = energy released to the room

=> Answer = 492 J

3. How much heat is needed to raise the temperature of 45g of water by 63oC? Joules

Formula: heat = mass * specific heat * ΔT

specific heat of water = 4186 J / Kg °C

heat = 0.045 kg * 4186 J/kg °C * 63°C = 11,867.31 J
</span>
7 0
3 years ago
How much is 2/3 of 9 marbles?
Umnica [9.8K]
( 9 ÷ 3 ) x 2 = 3 x 2 = 6 marbles ;
4 0
3 years ago
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