Ask question

Ask question

All categories

2 years ago

10

Please answer this question :)

1 answer:

tatuchka [14]2 years ago

5 0

Answer:

2/5

Step-by-step explanation:

2/5

You might be interested in

Prove that 1/sin^2A -1/tan^2A= 1

Vika [28.1K]

Answer:

Step-by-step explanation:

$LHS =\dfrac{1}{Sin^{2} \ A }-\dfrac{1}{Tan^{2} \ A }\\\\\\ = \dfrac{1}{sin^{2} \ A}- \dfrac{1}{\dfrac{Sin^{2} \ A}{Cos^{2} \ A}}\\\\\\= \dfrac{1}{sin^{2} \ A } - \dfrac{Cos^{2} \ A}{Sin^{2} \ A}\\\\\\= \dfrac{1-Cos^{2} \ A}{Sin^{2} \ A}\\\\\\= \dfrac{Sin^{2} \ A}{Sin^{2} \ A}\\\\\\= 1 = \ RHS$

Hint: 1 - Cos² A = Sin² A

4 0

2 years ago

Find at least three nonzero terms (including a 0 and at least two cosine terms and two sine terms if they are not all zero) of

Ainat [17]

You could subtract the denominator fro the numerator which would give you a total sum of 1 thousand an fifty five

7 0

3 years ago

What is the absolute value of 2 1/3

taurus [48]

2/12 is the correct answer

3 0

3 years ago

Read 2 more answers

What formula do we use to find slope?

Kamila [148]

Answer:Remember, the formula for slope is (y2 - y1) / (x2 - x1).

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Find the simple interest and amount when principal = Rs. 6000, rate = 6% per annum and time = 4 years

Alinara [238K]

Given:

Principal = Rs. 6000

Rate of simple interest = 6% per annum.

Time = 4 years

To find:

The simple interest and amount.

Solution:

Formula for simple interest:

$I=\dfrac{P\times r\times t}{100}$

Where, P is principal, r is the rate of interest and t is the number of years.

Putting P=6000, r=6 and t=4, we get

$I=\dfrac{6000\times 6\times 4}{100}$

$I=60\times 6\times 4$

$I=1440$

Now,

$Amount=Principal+Interest$

$Amount=6000+1440$

$Amount=7440$

Therefore, the simple interest is Rs. 7440 and the amount is Rs 7440.

7 0

3 years ago