The two real values that are not in the domain of the composition are x = 2 and x = -2.
<h3>
What two numbers are not in the domain of f°g?</h3>
Here we have:
f(x) = 1/x
g(x) = x^2 - 4
The composition is:
f°g = f(g(x)) = 1/(x^2 - 4)
The two values that are not in the domain are the values of x such that g(x) = 0, because we can't divide by zero.
g(x) = 0 = x^2 - 4
4 = x^2
±√4 = x
±2 = x
So g(x) = 0 when x = 2 or x = -2, so these are the two real values that are not in the domain of f°g.
If you want to learn more about domains:
brainly.com/question/1770447
#SPJ1
Answer:
<u>let's simplify the parenthesis first ~</u>
<u>now , bring the like terms at one side of the equation !</u>
<u>dividing</u><u> both sides of the equation by 30 ,</u>
hope helpful :)
Answer:
X=6
Step-by-step explanation:
would you like me to show how?
Answer:
60
Step-by-step explanation:
<H + <T = 180
2x+ 60 + x + 30 = 180
3x + 90 = 180
3x = 90
x = 30
<T = x + 30 = 30 + 30 = 60
Answer
<T = 60
