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Minchanka [31]
3 years ago
8

ANHL player's labor negotiating committee is to be selected from 8 player representatives from the Eastern Conference and 7 play

er representatives from the Western Conference. Find the probability of selecting 3 Eastern Conference representatives and 2 Western Conference representatives.
a. 1/ 3003
b. 1/3
c. 56/143
d. 140/429
Mathematics
1 answer:
cestrela7 [59]3 years ago
6 0

Answer:

21 / 143

Step-by-step explanation:

Given that:

Number of Eastern conference reps = 8

Number of western conference rep = 7

Probability of selecting 3 from Eastern reps and 2 from western reps

Probability = required outcome / Total possible outcomes

Total possible outcomes:

selection to be made = 3+ 2 = 5

Total Number of players = 8 +7 = 15

Total possible outcomes

Using combination formula :

nCr = n! / (n-r)!r!

15C5 = 15! / 10!5! = (15 * 14 * 13 * 12 * 11) / (5*4'3*2*1) = 360360 / 120 = 3003

Total possible outcomes = 3003

Required outcome :

8C3 * 7C2

8C3 = 56 ; 7C2 = 21

8C3 * 7C2 = 56 * 21 = 1176

required outcome / Total possible outcomes

= 1176 / 3003

= 21 / 143

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Given the functions f(x) = 2x -1 and g(x) =
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Answer:

Please check the explanation.

Step-by-step explanation:

Given

  • f(x) = 2x - 1
  • g(x) =  2 - x

a)

f(x) + g(x) = (2x - 1) + (2 - x)

                = 2x -1 + 2 - x

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b)

f(x) - g(x) = (2x - 1) - (2 - x)

              = 2x - 1 - 2 + x

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c)

g(-5) - f(-5)

Putting x = -5 in g(x) = 2 - x

g(x) = 2 - x

g(-5) = 2 - (-5) = 2+5 = 7

Putting x = -5 in f(x) = 2x - 1

f(x) = 2x - 1

f(-5) = 2(-5) - 1

       = -10 - 1

        = -11

Thus,

g(-5) - f(-5) = 7 - (-11) = 7+11 = 18

d)

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6 0
3 years ago
Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms
miv72 [106K]

<u>Hint </u><u>:</u><u>-</u>

  • Break the given sequence into two parts .
  • Notice the terms at gap of one term beginning from the first term .They are like \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} . Next term is obtained by multiplying half to the previous term .
  • Notice the terms beginning from 2nd term , 4,7,10,13 . Next term is obtained by adding 3 to the previous term .

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} .

We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]

Notice the term \dfrac{1}{2^{25}} will be too small , so we can neglect it and take its approximation as 0 .

\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]

\\\implies \boxed{ S_1 \approx 1 }

\rule{200}2

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

\implies S_2=\dfrac{n}{2}[2a + (n-1)d]

Substitute ,

\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}

Hence sum = 908 + 1 = 909

7 0
2 years ago
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